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Temka [501]
3 years ago
9

Two cars A and B leave an intersection at the same time. Car A travels west at an average speed of x miles per hour and car B tr

avels south at an average speed of y miles per hour. Write a program that prompts the user to enter the average speed of both the cars and the elapsed time (in hours and minutes) and outputs the (shortest) distance between the cars.
Engineering
1 answer:
svet-max [94.6K]3 years ago
7 0

Answer:

Distance between A & B, dAB, is hypotenus.

dAB²=dA²+dB²

A'=70 mph, B'=55mph, (convert t to hours)

dA=A'•t, dB=B'•t

dAB=√((70t)²+(55t)²)

Explanation:

Distance between A & B, dAB, is hypotenus.

dAB²=dA²+dB²

A'=70 mph, B'=55mph, (convert t to hours)

dA=A'•t, dB=B'•t

dAB=√((70t)²+(55t)²)

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La altura es de 169.4 metros.

Dado que las dos torres que sostienen un puente colgante tienen una separación de 240m y una altura de 110m a partir de la carretera, si el cable tensor más corto mide 10m, para determinar cuál es altura de un cable que se encuentra a 100m de distancia del centro se debe realizar los siguientes cálculos, aplicando la ecuación parabólica:  

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