Answer:
The mass flow rate of the mixture in the manifold is 6.654 kg/min
Explanation;
In this question, we are asked to calculate mass flow rate of the mixture in the manifold
Please check attachment for complete solution and step by step explanation.
Answer:
Explanation:
For this case we have given the following data:
represent the temperature for the air
represent the velocity of the air
represent the specific heat ratio at the room
represent the gas constant for the air
And we want to find the velocity of the air under these conditions.
We can calculate the spped of the sound with the Newton-Laplace Equation given by this equation:
Where K = is the Bulk Modulus of air, k is the adiabatic index of air= 1.4, R = the gas constant for the air, the density of the air and T the temperature in K
So on this case we can replace and we got:
The Mach number by definition is "a dimensionless quantity representing the ratio of flow velocity past a boundary to the local speed of sound" and is defined as:
Where v is the flow velocity and the volocity of the sound in the medium and if we replace we got:
And since the Ma<0.8 we can classify the regime as subsonic.
Answer:
3021.7 N/m^2 or 3.022 kN/m^2
Explanation:
The area of the interior column is equivalent to 6*6 = 36 m^2. The length of the structure is 4790 N/m^2. The live load element factor (
) is 4. The reduced live load will be:
L = =
Therefore, the value of the reduced live load that will be supported by the column is 3021.7 N/m^2 or 3.022 kN/m^2.
This is less than 0.4* = 0.4*4790 = 1916 N/m^2