Answer:
105 m/s
Explanation:
Given that the speed of train A,
= 45 m/s from west to east.
Speed of train B,
= 60 m/s from east to west.
Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.
So, the speed of train A from east to west= - 45 m/s
The speed of train B w.r.t train A
m/s
Hence, the speed of train B w.r.t train A is 105 m/s from east to west.
The force of gravity between two objects is given by:

where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation
In this problem, the mass of the object is

, while the Earth's mass is

. Their separation is

, therefore the gravitational force exerted on the object is
Answer:
v = 6i + 12j + 4k
Explanation:
Find the magnitude of the direction vector.
√(3² + 6² + 2²) = 7
Normalize the direction vector.
3/7 i + 6/7 j + 2/7 k
Multiply by the magnitude of v.
v = 14 (3/7 i + 6/7 j + 2/7 k)
v = 6i + 12j + 4k
Answer:
The given circuit diagram shows parallel circuit.
Explanation:
In this circuit diagram two bulbs are connected in parallel combination because current flows from the battery gets bifurcated at the junction. Thus, two bulbs are connected in parallel combination.
This parallel combinations of bulbs then connected to the battery given in the diagram. So, the combinations of bulbs are connected in parallel combinations with the battery.
Hence, both bulbs and battery are connected in parallel combinations with each other.
The circuit diagram shown in figure is parallel.
Answer:
See explanation
Explanation:
We have to convert to angular velocity in rads-1 as follows;
Angular velocity in rad/s = 2π/60 × 1900 rpm = 199 rad/s
Given that
angular velocity =angle turned /time taken
Time taken = angle turned/angular velocity
Converting 35° to radians we have;
35 × π/180 = 0.61 radians
Time taken = 0.61 radians/199 rad/s
Time taken = 0.0031 seconds