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grandymaker [24]
2 years ago
13

A person is using a rope to lower a 8.0-N bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc

e exerted by the rope on the bucket
Physics
1 answer:
Stells [14]2 years ago
8 0

The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

<h3>What's force?</h3>
  • According to Newton's second law, force is expressed as rate of change of momentum.
  • It can be written as mass × acceleration.
<h3>What's the force experienced by an object, when it moves with constant velocity?</h3>
  • When an object moves with constant velocity, its acceleration is zero.
  • Since acceleration is zero, so the force experienced by it is zero.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

Learn more about the force here:

brainly.com/question/12785175

#SPJ4

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Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot
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Answer:0.27

Explanation:

Given

One worker Pushes with force F_1=430 N

other Pulls it with a rope of rope F_2=360 N

mass of crate m=290 kg

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

f_r=F_1+F_2

where f_r is the friction force

f_r=430+360

f_r=790 N

f_r=\mu N

where \muis the coefficient of static friction

N=mg

790=\mu 29\cdot 9.8

\mu =0.27

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How much heat (in calories) are needed to raise the temperature of 60 g of water
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Answer:

Well, each ml of water requires one calorie to go up 1 degree Celsius, so this liter of water takes 1000 calories to go up 1 degree Celsius.

Explanation:

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For the different values given for the radius of curvature RRR and speed vvv, rank the magnitude of the force of the roller-coas
nirvana33 [79]

Explanation:

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Case 1.

R = 60 m v = 16 m/s

F=\dfrac{(16)^2m}{60}=4.26m\ N

Case 2.

R = 15 m v = 8 m/s

F=\dfrac{(8)^2m}{15}=4.26m\ N

Case 3.

R = 30 m v = 4 m/s

F=\dfrac{(4)^2m}{30}=0.54m\ N

Case 4.

R = 45 m v = 4 m/s

F=\dfrac{(4)^2m}{45}=0.36m\ N

Case 5.

R = 30 m v = 16 m/s

F=\dfrac{(16)^2m}{30}=8.54m\ N

Case 6.

R = 15 m v =12 m/s

F=\dfrac{(12)^2m}{15}=9.6m\ N

Ranking from largest to smallest is given by :

F>E>A=B>C>D

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