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grandymaker [24]
1 year ago
13

A person is using a rope to lower a 8.0-N bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc

e exerted by the rope on the bucket
Physics
1 answer:
Stells [14]1 year ago
8 0

The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

<h3>What's force?</h3>
  • According to Newton's second law, force is expressed as rate of change of momentum.
  • It can be written as mass × acceleration.
<h3>What's the force experienced by an object, when it moves with constant velocity?</h3>
  • When an object moves with constant velocity, its acceleration is zero.
  • Since acceleration is zero, so the force experienced by it is zero.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

Learn more about the force here:

brainly.com/question/12785175

#SPJ4

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A student (m = 68 kg) falls freely from rest and strikes the ground. During the collision with the ground, he comes to rest in a
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Answer:

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Explanation:

Here the potential and kinetic energy will balance each other

mgh=\frac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}

This is the initial velocity of the system and the final velocity is 0

t = Time taken = 0.04 seconds

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Equation of motion

v=u+at\\\Rightarrow a=\frac{v-u}{t}

From Newton's second law

F=ma\\\Rightarrow F=m\frac{v-u}{t}\\\Rightarrow 18000=68\frac{0-\sqrt{2gh}}{0.04}\\\Rightarrow \frac{18000}{68}\times 0.04=-\sqrt{2\times 9.81\times h}\\\Rightarrow 10.58823=-\sqrt{2\times 9.81\times h}

Squarring both sides

112.11061=2\times 9.81\times h\\\Rightarrow h=\frac{112.11061}{2\times 9.81}\\\Rightarrow h=5.7141\ m

The height from which the student fell is 5.7141 m

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