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grandymaker [24]
2 years ago
13

A person is using a rope to lower a 8.0-N bucket into a well with a constant speed of 2.0 m/s. What is the magnitude of the forc

e exerted by the rope on the bucket
Physics
1 answer:
Stells [14]2 years ago
8 0

The magnitude of the force exerted by the rope on the bucket is 8N.

To find the answer, we need to know about the force.

<h3>What's force?</h3>
  • According to Newton's second law, force is expressed as rate of change of momentum.
  • It can be written as mass × acceleration.
<h3>What's the force experienced by an object, when it moves with constant velocity?</h3>
  • When an object moves with constant velocity, its acceleration is zero.
  • Since acceleration is zero, so the force experienced by it is zero.

Thus, we can conclude that there's no force on the bucket by the person as he is lowering it by constant velocity. But force on the bucket by the rope is 8N.

Learn more about the force here:

brainly.com/question/12785175

#SPJ4

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What is the Coriolis effect? Explain how<br> this works
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3 years ago
A certain electromagnetic wave traveling in seawater was observed to have an amplitude of 98.02 (V/m) at a depth of 10 m, and an
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Answer:

The  value is   \alpha =  0.002 Np/m

Explanation:

From the question we are told that

  The first amplitude of the wave is  E_{max}1 =  98.02 \  V/m

  The first  depth  is  D_1 =  10 \  m

   The second amplitude is  E_{max}2 =  81.87 \  (V/m)

   The second depth is D_2 = 100 \ m

Generally from the spatial wave equation we have

   v(x) =  Ae^{-\alpha d}cos(\beta x  + \phi_o)

=>       \frac{v(x)}{v(x)} =\frac{  Ae^{-\alpha d}cos(\beta x  + \phi_o)}{ Ae^{-\alpha d}cos(\beta x  + \phi_o)}

So considering the ratio of the equation for the  two depth

\frac{A}{A_S}  =  \frac{e^{-D_1 \alpha }}{e^{-D_2 \alpha }}

=>   \frac{98.02}{81.87}  =  \frac{e^{-10 \alpha }}{e^{-100 \alpha }}

=>   \alpha  =  \frac{0.18}{90}

=>    \alpha =  0.002 Np/m

       

4 0
3 years ago
evaluate the force of a skateboard exerts on you if your mass is 60kg and you push on the skateboard with a force of 60N
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Every action has an equal or opposite reaction.
You weigh 60kg 
<span>So your acceleration is 6N / 60 kg = 0.1m/s^2</span>
6 0
3 years ago
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