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omeli [17]
2 years ago
6

Lab: Waves and Diffraction Assignment: Lab Report Anyone have this completed

Physics
1 answer:
Julli [10]2 years ago
6 0

Explanation:

Theoretical Discussion

The diffraction of classical waves refers to the phenomenon wherein the waves encounter an obstacle that

fragments the wave into components that interfere with one another. Interference simply means that the

wavefronts add together to make a new wave which can be significantly different than the original wave. For

example, a pair of sine waves having the same amplitude, but being 180◦ out of phase will sum to zero, since

everywhere one is positive, the other is negative by an equal amount.

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Heat transfer is the answer
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3 years ago
Compare blue and red light from the visible spectrum. which has: the longer wavelength? the greater frequency? the greater energ
Hitman42 [59]
1) By looking at the table of the visible spectrum, we see that blue light has a wavelength in the range [450-490 nm], while red light has wavelength in the range [620-750 nm]. Therefore, red light has longer wavelength than blue light.

2) The frequency f of an electromagnetic wave is related to its wavelength \lambda by the formula
f= \frac{c}{\lambda}
where c is the speed of light. We see that the frequency is inversely proportional to the wavelength, so the shorter the wavelength, the greater the frequency. In this case, blue light has shorter wavelength than red light, so blue light has greater frequency than red light.

3) The energy of the photons of an electromagnetic wave is given by
E=hf
where h is the Planck constant and f is the frequency. We see that the energy is directly proportional to the frequency, so the greater the frequency, the greater the energy. In this problem, blue light has greater frequency than red light, so blue light has also greater energy than red light.
6 0
3 years ago
Match the statements below.
Artemon [7]
Constant velocities is an objects velocity is not changing.This means it is moving at the same speed.
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5 0
3 years ago
A current of 0.92 a flows in a wire. how many electrons are flowing past any point in the wire per second? the charge on one ele
Fantom [35]
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval, \Delta t:
I= \frac{Q}{\Delta t}
First we need to find the net charge flowing at a certain point of the wire in one second, \Delta t=1.0 s. Using I=0.92 A and re-arranging the previous equation, we find
Q=I \Delta t= (0.92 A)(1.0 s)=0.92 C

Now we know that each electron carries a charge of e=1.6 \cdot 10^{-19} C, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
N= \frac{Q}{q} = \frac{0.92 C}{1.6 \cdot 10^{-19} C}=5.75 \cdot 10^{18}
3 0
3 years ago
Grain is pouring into a silo to be stored for later use. Due to the friction between pieces of grain as they rub against each ot
jolli1 [7]

Answer:

The electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

Explanation:

Given:

Charge on one grain, Q_{1}=6\times 10^{-10}\textrm{ C}

Charge on another grain, Q_{2}=2.3\times 10^{-15}\textrm{ C}

Separation between them, d=2\textrm{ cm}=0.02\textrm{ m}

Electric force acting between two charges Q_{1}\textrm{ and }Q_{2} separated by a distance d is given as:

F_{elec}=\frac{kQ_{1}Q_{2}}{d^2}

Where, k is Coulomb's constant equal to 9\times 10^9\textrm{ }Nm^2/C^2.

Now, plug in all the values and solve for F{elec}.

F{elec}=\frac{9\times 10^9\times 6.0\times 10^{-10}\times 2.3\times 10^{-15}}{(0.02)^2}\\\\F_{elec}=3.15\times 10^{-11}\textrm{ N}

Therefore, the electric force between them if the pieces of grain are 2 cm apart is 3.15\times 10^{-11}\textrm{ N}.

3 0
3 years ago
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