Answer:
Explanation:
Flux through the coil = nBA , n is no of turns , B is magnetic flux and A a is area of the coli
= 200 x 5.6 x 10⁻⁵ x 11.8 x 10⁻⁴
= 13216 x 10⁻⁹ weber .
b ) When the coil becomes parallel to magnetic field , flux through it will become zero.
c ) e m f induced = change in flux / time
= 13216 x 10⁻⁹ / 4.9 x 10⁻²
= 2697.14 x 10⁻⁷ V
= 269.7 x10⁻⁶
269.7 μV.
Answer:
The speed of the ball was, v = 3 m/s
Explanation:
Given data,
The time period of the ball, t = 8 s
The distance the ball rolled, d = 24 m
The velocity of an object is defined as the object's displacement to the time taken. The formula for the velocity is,
v = d / t m/s
Substituting the given values in the above equation,
v = 24 / 8
= 3 m/s
Hence, the speed of the ball was, v = 3 m/s
Answer:
The potential difference is 121.069 V
Solution:
As per the question:
Diameter of the cylinder, d = 9.0 cm = 0.09 m
Length of the cylinder, l = 40 cm = 1.4 m
Average Resistivity, ![\rho = 5.5\ \Omega-m](https://tex.z-dn.net/?f=%5Crho%20%3D%205.5%5C%20%5COmega-m)
Current, I = 100 mA = 0.1 A
Now,
To calculate the potential difference between the hands:
Cross- sectional Area of the Cylinder, A = ![\pi (\frac{d}{2})^{2} = 6.36\times 10^{- 3}\ m^{2}](https://tex.z-dn.net/?f=%5Cpi%20%28%5Cfrac%7Bd%7D%7B2%7D%29%5E%7B2%7D%20%3D%206.36%5Ctimes%2010%5E%7B-%203%7D%5C%20m%5E%7B2%7D)
Resistivity is given by:
![\rho = R\frac{A}{l}](https://tex.z-dn.net/?f=%5Crho%20%3D%20R%5Cfrac%7BA%7D%7Bl%7D)
![R = \rho \frac{l}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Crho%20%5Cfrac%7Bl%7D%7BA%7D)
![R = 5.5\times \frac{1.4}{6.36\times 10^{- 3}} = 1210.69\ \Omega](https://tex.z-dn.net/?f=R%20%3D%205.5%5Ctimes%20%5Cfrac%7B1.4%7D%7B6.36%5Ctimes%2010%5E%7B-%203%7D%7D%20%3D%201210.69%5C%20%5COmega)
Now, using Ohm's Law:
V = IR
![V = 0.1\times 1210.69 = 121.069\ V](https://tex.z-dn.net/?f=V%20%3D%200.1%5Ctimes%201210.69%20%3D%20121.069%5C%20V)