Answer:
Width of the slit will be equal to 1.47 mm
Explanation:
We have given wavelength of the light 
Distance D = 8 m
Distance between first minimum dark fringe and the central maximum is 2 mm
So 
We have to find the width of the slit
For the first order wavelength is equal to
, here a width of slit
So 
So width of the slit will be equal to 1.47 mm
Answer:
T = 19.75 N
Explanation:
given,
mass of ball = 0.25 Kg
radius = 0.5 m
frequency = 2 s⁻¹
tension in the string = ?
angular velocity
ω = 2 π f
ω = 2 π x 2
ω = 12.57 rad/s
tension on the string is equal to the centripetal force
T = m ω² r
T = 0.25 x 12.57² x 0.5
T = 19.75 N
Tension in the string is equal to T = 19.75 N
The answer is going be desert.
Answer:k=28.29 kN/m
Explanation:
Given
mass 
height from which Elevator falls 
Let x be the compression in the spring
thus From conservation of Energy Potential energy will convert in to Elastic Potential Energy of spring
----------1
also maximum acceleration is 5g
thus

here 


Substitute x in equation 1




