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IgorC [24]
3 years ago
9

The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm. Rounded to the nearest tent

h, what is the greatest possible value of x? 6.3 6.4 7.0 7.1
Mathematics
2 answers:
Flura [38]3 years ago
8 0

Answer:

7.1

Step-by-step explanation:

because pythagorean theorem

c² > a² + b²

20² > x² + 3x²

400 > 4x²

÷4      ÷4

100 > x²

  10 > x           400 > 4(7.1)²

                      400 > 4(50.41)

                      400 > 201.64

tankabanditka [31]3 years ago
6 0
Obtuse triangle Pythagorean Theorem

c² > a² + b²

20² > x² + 3x²
400 > 4x²
<u>÷4      ÷4</u>
<u> 100 > x²</u>
   10 > x
  
400 > 4(7.1)²
400 > 4(50.41)
400 > 201.64

The greatest possible value of x is 7.10
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Step-by-step explanation:

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6 0
3 years ago
6.8x+9.3 = -9.4+3,4(2-5x)<br> 6.8x+9.3 = -9.4+6.8 -17<br> 6.8x+9.3 = -2.6-17x
Advocard [28]

Answer:

x = -0.5

Step-by-step explanation:

From your last step:

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We have two terms with x in them on different sides of the equation, so we want to bring the 'x terms' over to the same side.

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7 0
4 years ago
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