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Natalka [10]
3 years ago
6

What would happen if CH4 was removed from the following reaction that has reached equilibrium? CO (g) + 3H2 (g) Two arrows stack

ed on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH4 (g) + H2O (g)
Chemistry
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

The equilibrium will shift to the right, towards the products

Explanation:

According to Le Chatelier's principle, when a reaction at equilibrium is subjected to changes in pressure, temperature, concentration etc then the equilibrium will shift in a direction to undo the effect of the induced change.

The given reaction is:

CO(g) + 3H2(g) ↔ CH4(g) + H2O(g)

If CH4 were removed from the reaction, then the equilibrium will shift in a direction to facilitate the production of more CH4 i.e. it shift to the right, favoring the products.

Anton [14]3 years ago
7 0
When  you  remove  CH4  to  a  reaction  that  reaches    equilibrium  The  Top  arrow  point  to  the  right.This  is  because  CH4 is  in  the  product  side  and  by  removing  it  the  number  of  moles   in  the  product  is  lowered  thus   favoring the  forward  reaction
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When two monosaccharides condense to form a disaccharide, what is the other product of the reaction? enter the molecular formula
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When two monosaccharides combine to make a disaccharide, water is the byproduct.

<h3>What are monosaccharides ?</h3>

The most fundamental building blocks from which all carbohydrates are constructed are monosaccharides, commonly known as simple sugars. They are the most basic types of sugar. They are typically crystalline solids, colorless, and soluble in water.

These three monosaccharides—glucose, fructose, and galactose—are crucial for nutrition. Six carbon atoms, twelve hydrogen atoms, and six oxygen atoms make up each single sugar molecule.

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4 0
1 year ago
In an experiment, a compound was determined to contain 68.94% oxygen and 31.06% of an unknown element by weight. The molecular w
monitta

Answer is: the compound is B₂O₃.

ω(O) = 68.94% ÷ 100%.

ω(O) = 0.6894; percentage of oxygen in the compound.

ω(X) = 31.06% ÷ 100%.

ω(X) = 0.3106; percentage of unknown element in the compound.

If we take 69.7 grams of the compound:

M(compound) = 69.7 g/mol.

n(compound) = 69.7 g ÷ 69.7 g/mol.

n(compound) = 1 mol.

n(O) = (69.7 g · 0.6894) ÷ 16 g/mol.

n(O) = 3 mol.

M(compound) = n(O) · M(O) + n(X) · M(X).

n(X) = 1 mol ⇒ M(X) = 21.7 g/mol; there is no element with this molecular weight.

n(X) = 2 mol ⇒ M(X) = 10.85 g/mol; this element is boron (B).

8 0
3 years ago
A _ reaction occurs when a substance usually containing carbon reacts with oxygen to produce energy in the form of light and hea
trapecia [35]
A COMBUSTION reaction occur when a substance ...........................................
Combustion reaction is also known as burning. It occurs when an hydrocarbon react with oxygen to yield carbon dioxide, water and energy in the form of light and heat. Combustion reaction can not take place in the absence of oxygen.
3 0
4 years ago
Sheena wants to measure the volume of a ball that is 24 cm across. How should she set up her equation?
Ksivusya [100]

Answer:

The volume of a ball that is 24 cm across is :

d). v = four-thirds pi 12 cubed

Explanation :

Ball is a sphere and volume of sphere is given by :

\frac{4}{3}\Pi r^{3}

r = radius of ball

r =\frac{24}{2}

r = 12 cm

Volume is :

\frac{4}{3}\Pi \times 12^{3}

8 0
4 years ago
Read 2 more answers
10. What could the pH of a solution be if a cyanidin indicator turned blue? What is used to determine the endpoint of a titratio
Leviafan [203]

Answer:

The cyanidin indicator turns blue within a pH range of 5 - 7. The pH of the solution could be 5, 6 or 7.

An indicator is used to determine the endpoint of a titration.

Explanation:

Cyanidin indicator changes colour with each change in pH. In acidic solutions (pH < 7) cyanidin indicator will turn red, through to purple and blue, while in basic solutions (pH > 7), cyanidin indicator will change colour from aquamarine through to green and yellow. The cyanidin indicator turns blue within a pH range of 5 - 7.

Titration is a technique used in analytical chemistry to determine the unknown concentration of a solution. A solution of known concentration is added from a burette to the solution of unknown concentration until the reaction between the two solutions is complete. This known as the endpoint of the experiment. The endpoint of a titration is determined using an indicator which is added to reaction mixture. A colour charge is produced by the indicator at the endpoint of the reaction.

Note: An indicator is a dye of weak organic acids or bases which changes colour with changes in the pH of a solution. Some common indicators are methyl orange, methyl red, phenolphthalein, etc. These indicators are used to monitor the changes in the pH of solutions during a reaction.

7 0
3 years ago
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