Question

What would happen if CH4 was removed from the following reaction that has reached equilibrium? CO (g) + 3H2 (g) Two arrows stacked on top of each other. The top arrow points to the right. The bottom arrow points to the left. CH4 (g) + H2O (g)

Answer 1

Answer:

The equilibrium will shift to the right, towards the products

Explanation:

According to Le Chatelier's principle, when a reaction at equilibrium is subjected to changes in pressure, temperature, concentration etc then the equilibrium will shift in a direction to undo the effect of the induced change.

The given reaction is:

CO(g) + 3H2(g) ↔ CH4(g) + H2O(g)

If CH4 were removed from the reaction, then the equilibrium will shift in a direction to facilitate the production of more CH4 i.e. it shift to the right, favoring the products.

Answer 2

When  you  remove  CH4  to  a  reaction  that  reaches    equilibrium  The  Top  arrow  point  to  the  right.This  is  because  CH4 is  in  the  product  side  and  by  removing  it  the  number  of  moles   in  the  product  is  lowered  thus   favoring the  forward  reaction