Answer:
Explanation:
Given
slit width 
wavelength of light 
Screen is placed at a distance of 
The angle for the first minima is given by
for m=1
and one half of central maxima is given by
Width of central maxima 
Answer:
why we follow ur order..........
Answer:
According to Kepler's 3rd law.
It states that the orbital period, T is related to the distance, r as:
T²
= 4
π²r³
/G M
where G is the universal gravitational constant = 6.673 × 10⁻¹¹ Nm²/kg²
Rearranging for M should give Jupiter's mass.
M =
4
π²r³/GT²
T= 1.77 days × 24 h/day × 60 min/h × 60 s/min = 1.53 × 10⁵ s
r = 4.22x10⁸ m
M = 4π² ((4.22 × 10⁸ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (1.53 × 10⁵ s)²)
M = 1.90 × 10²⁷kg
The mass of Jupiter is 1.90 × 10²⁷kg.
1.90 × 10²⁷kg
T= 7.16 days × 24 h/day × 60 min/h × 60 s/min = 6.19 × 10⁵s
r = 1.07x10⁹ m
M = 4π² ((1.07 × 10⁹ m)³/(6.673 × 10⁻¹¹ Nm²/kg² x (6.19 × 10⁵ s)²)
M = 1.90 × 10¹⁷kg
The mass of Jupiter is 1.90 × 10¹⁷kg.
THE RESULTS TO PART A and B ARE NOT CONSISTENT. The reason is because of the difference in radius of each satellites from Jupiter. i.e the farther away the moons, the smaller they become in space and the more the number of days to complete an orbit.
Answer:
ΔT = 0.02412 s
Explanation:
We will simply calculate the time for both the waves to travel through rail distance.
FOR THE TRAVELING THROUGH RAIL:
FOR THE WAVE TRAVELING THROUGH AIR:
The separation in time between two pulses can now be given as follows:
<u>ΔT = 0.02412 s</u>
The speed of light (electromagnetic radiation) is equal to 299 792 458
m / s or 3x10^8 m/s in scientific notation.
So with this information, we could now look for the
distance. Solution:
Take note that μs means microseconds.
Speed of light * microseconds travelled * actual amount of microseconds
(3x10^8 m/s) (45.0 μs) (1x10^-6 s/μs) = 13,500 m.
