Question

A force of 6.0 N pulls a box 0.40 m along a frictionless plane that is inclined at 36°. What work is being done by the pulling force?

Answer 1

Answer:

Expression of work done is

$W = Fd cos\theta$

Work done to move the sled is given as 1.94 J

Explanation:

As we know that the formula of work done is given as

$W = Fd cos\theta$

here we know that

F = 6 N

d = 0.4 m

$\theta = 36 degree$

so we will have

$W = 6 \times 0.4 cos36$

$W = 1.94 J$