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slamgirl [31]
3 years ago
12

Calcium carbonate, when heated, forms calcium oxide and carbon dioxide. 100grams of calcium carbonate will produce 56grams of ca

lcium oxide. How many grams of carbon dioxide will it produce? Show working out
Chemistry
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

It will produce 44 grams of carbon dioxide

Explanation:

Step 1: Data given

MAss of CaCO3 = 100 grams

Molar mass of CaCO3 = 100.09 g/mol

Mass of CaO produced = 56 grams

Molar mass of CaO = 56.08 g/mol

Step 2: The balanced equation

CaCO3 → CaO + CO2

Step 3: Calculate moles CaCO3

Moles CaCO3 = mass CaCO3 / molar mass CaCO3

Moles CaCO3 = 100 grams / 100.09 g/mol

Moles CaCO3 = 1.00 moles

Step 4: Calculate moles CaO

Moles CaO = 56 grams / 56.08 g/mol

Moles CaO = 1.00 moles

Step 5: Calculate moles CO2

For 1 mol CaCO3 we'll have 1 mol 1 mol CaO and 1 mol CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 1.00 moles * 44.0 g/mol

Mass CO2 = 44 grams

It will produce 44 grams of carbon dioxide

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Given 3.4 grams of x compound with a molar mass of 85 g and 4.2 grams of y compound with a molar mass of 48 g How much of compou
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Answer:

4.36~g~XY

Explanation:

In this case, we can start with the reaction:

2X + Y_2~->~2XY

If we check the reaction, we will have 2 X and Y atoms on both sides. So, <u>the reaction is balanced</u>. Now, the problem give to us two amounts of reagents. Therefore, we have to find the <u>limiting reagent</u>. The first step then is to find the moles of each compound using the <u>molar mass</u>:

3.4~g~X\frac{1~mol~X}{85~g~X}=0.04~mol~X

4.2~g~Y_2\frac{1~mol~Y_2}{48~g~Y_2}=0.0875~mol~Y_2

Now, we can <u>divide by the coefficient</u> of each compound (given by the balanced reaction):

\frac{0.04~mol~X}{1}=~0.04

\frac{0.0875~mol~Y_2}{2}=0.04375

The smallest value is for "X", therefore this is our <u>limiting reagent</u>. Now, if we use the <u>molar ratio</u> between "X" and "XY" we can calculate the moles of XY, so:

0.04~mol~X\frac{2~mol~XY}{2~mol~X}=0.04~mol~XY

Finally, with the molar mass of "XY" we can calculate the grams. Now, we know that 1 mol X = 85 g X and 1 mol Y_2 = 48 g Y_2 (therefore 1 mol Y = 24 g Y). With this in mind the <u>molar mass of XY</u> would be 85+24 = 109 g/mol. With this in mind:

0.04~mol~XY\frac{109~g~XY}{1~mol~XY}=4.36~g~XY

I hope it helps!

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1.125

Explanation:

I think it is his because if you add 0.30 and 0.15 it adds up to 0.45 so you just multiply 0.45 and 2.5 and then it gives you 1.125. HOPE IT HELPS.

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