Acceleration = (change in velocity) / (time for the change)
Change in velocity = (ending velocity) - (starting velocity)
Change in the plane's velocity = (10,000 m/s north) - (8,000 m/s north)
Change in the plane's velocity = 2,000 m/s north
Time for the change = 40 seconds
Acceleration = (2,000 m/s north) / (40 seconds)
<em>Acceleration = 50 m/s² north </em>
Answer:
v = 1.7 m/s
Explanation:
Given that,
Initial velocity of the object, u = 1 m/s
Acceleration of the object, a = 1 m/s²
We need to find the velocity of the object after moving 1 m. Let v be the velocity. Using third equation of kinematics to find it i.e.

So, the final velocity of the object is 1.7 m/s.
Answer:
Before the plank will tip cat will walk 1.652 m
Explanation:
Mass of the cat along with plank 
Center of mass of the plank 
Mass of cat 
We have to find how far right of sawhorse B.
Plank will tip when weight of the cat about B is greater than the torque by the weight of the plank.
Balancing the the torque



(89000/102000)×100
=87.25%
(92000/104000)×100
=88.46%
efficiency is (output/input)×100
if u get confused which way input and output should go, remember the smaller value is always output and it's above in the fraction, then only it's possible to get a efficiency lower than 100.
I believe the answer is C- payload