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Deffense [45]
3 years ago
7

A bird, accelerating from rest at a constant rate, experiences a displacement of 28 m in 11 s. what is the final velocity after

11 s?
Physics
1 answer:
frutty [35]3 years ago
4 0
Let's see what variables we've got first. Hmmm. We have:

Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)

And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.

I'm going to pick one of the motion equation to find more information:

d = ut +  \frac{1}{2} a {t}^{2}

I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.

Now I'm going to use another motion equation that has v in it because that needs to be solved!

v = u + at

Now I know everything except dial velocity v. Nice!

v = 0 + (0.4628)(11)
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solution

we know here potential difference that is express as

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so here

ln\frac{r2}{r1} = 2\pi \epsilon _o \times \frac{\triangle V}{\lambda }  

as here \lambda is linear charge density  

\frac{r2}{r1} = e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}  

r2 = r1 × e^{2\pi \epsilon _o \times \frac{\triangle V}{\lambda }}  

r2 = 2.40 × e^{2\pi 8.85\times 10^{-12} \times \frac{175}{15\times 10^{-6} }}  

r2 = 2.401557  cm

and

here distance above surface will be

distance = r1 - r2

distance =  2.50 - 2.40

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