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3 years ago

What is the work done by the electric force to move a 1 c charge from a to b?

Physics

1 answer:

frosja888 [35]3 years ago

4 0

The work done by the electric force to move a 1 c charge from a to b is

(the voltage at 'b' compared to 'a') volts .

That's because "volt" means "Joule per Coulomb" .

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Man start to moves from point A (Initial Point) to Point B (Final Point) in a given

mash [69]

Answer:

Image not full.

Explanation:

From what I can see, Displacement is 175m,

Distance will be = 100 + 50 + the hidden value on the bottom right

4 0

3 years ago

Does gravity always include the Earth’s pull or can it be between other objects?

padilas [110]

Well other planets have a gravitational pull that's what keep the planet's orbiting the sun. But the amount of gravity differs by mass.

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Assume that in 2010 the United States will need 2.0×1012 watts of electric power produced by thousands of 1000 MW power plants.

Alex73 [517]

Answer:

1752.14 tonnes per year.

Explanation:

To solve this exercise it is necessary to apply the concepts related to power consumption and power production.

By conservation of energy we know that:

$\dot{P} = \bar{P}$

Where,

$\dot{P} =$ Production of Power

$\bar{P} =$ Consumption of power

Where the production of power would be,

$\dot{P} = m \dot{E}\eta$

Where,

m = Total mass required

$\dot{E} =$ Energy per Kilogram

$\eta =$ Efficiency

The problem gives us the aforementioned values under a production efficiency of 45%, that is,

$\dot{P} = \bar{P}$

$m \dot{E}\eta = \bar{P}$

Replacing the values we have,

$m(8*10^13)(0.45) = 2*10^{12}$

Solving for m,

$m = \frac{ 2*10^{12}}{(8*10^13)(0.45)}$

$m = 0.0556 \frac{kg}{s}$

We have the mass in kilograms and the time in seconds, we need to transform this to tons per year, then,

$m = 0.556\frac{kg}{s}*(\frac{3.1536*10^7s}{1year})(\frac{1ton}{1000kg})$

$m = 1752.14$ tonnes per year.

8 0

3 years ago

(no links or files) What types of waves are shown in this image?

rewona [7]

Answer:

Absorbed and reflected

Explanation:

B is reflected because you can’t see the red arrow which represents a light that bounces off of it and a aired up sword because you can see it win through the object shown in the picture

3 0

3 years ago

Read 2 more answers

Si aplicamos una fuerza constante de 30 N sobre un cuerpo de 25 Kg, este se mueve de tal manera que en 5 s adquiere la velocidad

Ganezh [65]

Answer:

Si hay rozamiento y el valor de la fuerza de roce es 10 N

Explanation:

Fuerza Neta

La fuerza neta sobre un cuerpo es la suma vectorial de todas las fuerzas actuantes sobre el mismo.

Si conocemos el módulo de la fuerza neta F y la masa m del cuerpo, aplicamos la segunda ley de Newton para relacionarlas con la aceleración a:

$F=m.a$

Tenemos los datos cinemáticos de la situación, según la cual el cuerpo adquiere una velocidad (desde el reposo) de 4 m/s en 5 s.

Utilizamos la fórmula:

$v_f=v_o+a.t$

Y despejamos la aceleración:

$\displaystyle a=\frac{v_f-v_o}{t}$

$\displaystyle a=\frac{4-0}{5}$

$a=0.8 \ m/s^2$

Podemos calcular la aceleración real que el cuerpo adquiere, producto de una fuerza efectiva igual a:

$F_e=25\ Kg\cdot 0.8 \ m/s^2$

$F_e=20\ N$

Si se está aplicando una fuerza de $F_a= 30 N$ y solo 20 N producen movimiento, entonces se está perdiendo en rozamiento una fuerza:

$F_r=F_a-F_e=30 - 20=10$

$F_r=10\ N$

Si hay rozamiento y el valor de la fuerza de roce es 10 N

8 0

3 years ago