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deff fn [24]
3 years ago
11

The heating element in an automobile window

Physics
1 answer:
vovikov84 [41]3 years ago
5 0
There are 3 equations for power, P = VI = V^2/R = I^2/R

Given the values you have been given, we know we'll be using V^2/R.

Substituting the values in, we get:

P = 12^2/1.2 = 144/1.2 = 120W
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Describe the difference difference<br> between separation and division
aliina [53]
Separation is the propagation method in which these natural structures are simply removed from the parent plant and planted to grow on their own. When one of these structures is cut into sections that will then grow into a new plant the method is referred to as division.
3 0
3 years ago
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Tara's cell phone plan costs $39.00 a month, which includes 100 text messages. After she uses all of her text messages, it will
vekshin1
I think it is $585.hope it is right
5 0
3 years ago
Help please, I don't get it​
Sergio [31]

Answers:

a) \hat F=(0.83,-0.55) N

b) \hat D=(-0.44,-0.89) m

c) \hat V=(-0.47,0.88) m/s

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as \hat v and the way to calculate is as follows:

\hat v=\frac{\vec v}{|v|}

Where:

\vec v=(x,y) is the vector

|v|=\sqrt{x^{2}+y^{2}} is the magnitude of the vector

Having this information clarified, let's begin with the answers:

a) Force Vector

\vec F=(9.0 \hat i - 6.0 \hat j) N

Magnitude of \vec F:

|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N

<u />

<u>Unit vector:</u>

\hat F=\frac{\vec F}{|F|}

\hat F=\frac{(9.0 \hat i - 6.0 \hat j) N}{10.81 N}

\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N

\hat F=(0.83,-0.55) N

b) Displacement Vector

\vec D=(-4.0 \hat i - 8.0 \hat j) m

Magnitude of \vec D:

|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m

<u />

<u>Unit vector:</u>

\hat D=\frac{\vec D}{|D|}

\hat D=\frac{(-4.0 \hat i - 8.0 \hat j) m}{8.94 m}

\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m

\hat D=(-0.44,-0.89) m

c) Velocity Vector

\vec V=(-3.50 \hat i + 6.50 \hat j) m/s

Magnitude of \vec V:

|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s

<u />

<u>Unit vector:</u>

\hat V=\frac{\vec V}{|V|}

\hat V=\frac{(-3.50 \hat i +6.50 \hat j) m/s}{7.38 m/s}

\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s

\hat V=(-0.47,0.88) m/s

8 0
4 years ago
As you get closer toward the sun, what happens to the period of rotations of gas giants?
vaieri [72.5K]

Answer: try a

Explanation:

4 0
3 years ago
A guy wire 1034 feet long is attached to the top of a tower. When pulled taut, it touches level ground 699 feet from the base of
kolezko [41]

Answer:

80.386 degrees

Explanation:

We use the cosine equation here (which is the adjacent side of the unknown angle divided by the hypotenuse

The adjacent side = 699ft

The hypotenuse = 1034ft

using cos∅ = Adjacent/hypotenuse

where ∅ is the unknown angle

cos ∅ = 699/1034 = 0.167

∅ = arccos 0.167 = 80.368°

As easy as one can imagine

8 0
3 years ago
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