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m_a_m_a [10]
3 years ago
15

If you drop a steel metal ball off a building and it takes 3 seconds to hit

Physics
1 answer:
qwelly [4]3 years ago
5 0

Answer:

40\:\mathrm{m}

Explanation:

We can use kinematics equation \Delta y={v_i}^2+\frac{1}{2}at^2 to solve this problem. Because the metal ball's initial velocity was 0, {v_i}^2=0.

Therefore, our equation becomes:

\Delta y=\frac{1}{2}at^2 (freefall equation).

t is given as 3 seconds and a is acceleration due to gravity (9.81\:\mathrm{m/s}).

Therefore, our answer is:

\Delta y = \frac{1}{2}\cdot9.81\cdot3^2=44.145=\fbox{$40\:\mathrm{m}$} (one significant figure).

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