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3 years ago

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Two people are talking through a thick wall, 3 meters high, between them. This fact can best be explained by the phenomenon of A

) diffraction. B) refraction. C) reflection. D) polarization. E) none of the above

1 answer:

dezoksy [38]3 years ago

6 0

The answer is Ai just took it

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The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi

alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha t$

Put the value into the formula

$5.0-0=\alpha\times8.0$

$\alpha=\dfrac{5.0}{8.0}$

$\alpha=0.625\ rev/s^2$

We need to calculate the angular displacement

Using equation of angular motion

$\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta=0+\dfrac{1}{2}\times0.625\times(8.0)^2$

$\theta=20\ rev$

Now, The washer coming to rest from top spin

We need to calculate the angular acceleration

Using equation of angular motion

$\omega_{f}-\omega_{i}=\alpha t$

$\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}$

$\alpha=\dfrac{0-5}{12}$

$\alpha=−0.4167\ rev/s^2$

We need to calculate the angular displacement

Using formula of displacement

$\theta'=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta'=5\times12+\dfrac{1}{2}\times(-0.4167)\times12^2$

$\theta'=30\ rev$

We need to calculate the total number of revolution

$\theta''=\theta+\theta'$

$\theta''=20+30$

$\theta''=50\ rev$

Hence, The total number of revolution is 50 rev.

5 0

4 years ago

A jet aircraft is traveling at 262 m/s in horizontal flight. The engine takes in air at a rate of 85.9 kg/s and burns fuel at a

Fittoniya [83]

Answer:

$F_T=60132.52N$

$P=15814852.76W$

Explanation:

From the question we are told that

Velocity of aircraft $V=263m/s$

Engine air intake rate $\triangle M_a=85.9kg/s$

Fuel burn rate $\triangle M_f =3.92kg/s$

Velocity of exhaust gas $V_e =921m/s$

Generally the Mass change rate of Rocket is mathematically given by

$\triangle M = \triangle M_a+\triangle M_f$

$\triangle M= 85.9+3.92$

$\triangle M=89.82kg/s$

Generally the Trust of the rocket is given mathematically by

$F_T=(\triangle M *V_e)-(dM_a/dt)*(V)$

$F_T=(89.82 *921)-(85.9)*(263)$

$F_T=60132.52N$

Generally the Rocket's delivered power is mathematically given by

Delivered power P

$P=V*F_T$

$P=263*60132.52N$

$P=15814852.76W.$

8 0

3 years ago

explain the main development stages of the tropical hurricanes/cyclones and discuss their impacts according to the Saffir Simpso

Nana76 [90]

Answer:

The Saffir-Simpson Hurricane Wind Scale is a 1 to 5 rating based only on a hurricane's maximum sustained wind speed. This scale does not take into account other potentially deadly hazards such as storm surge, rainfall flooding, and tornadoes.

The Saffir-Simpson Hurricane Wind Scale estimates potential property damage. While all hurricanes produce life-threatening winds, hurricanes rated Category 3 and higher are known as major hurricanes*. Major hurricanes can cause devastating to catastrophic wind damage and significant loss of life simply due to the strength of their winds. Hurricanes of all categories can produce deadly storm surge, rain-induced floods, and tornadoes. These hazards require people to take protective action, including evacuating from areas vulnerable to storm surge.

Explanation:

pls mark as branlist.

5 0

3 years ago

HELP!! Physical or chemical property? For the questions..

Gnoma [55]

1.Chemical
2.Physical
3.Physical
4.Chemical
5Physical
I am not sure if these are right, but I hope I helped (:

3 0

3 years ago

A 1.4-µC point charge is placed between the plates of a parallel plate capacitor. The charge experiences a force of 0.59 N. What

solmaris [256]

Answer:

$\sigma=3.72\times 10^{-6}\ C/m^2$

Explanation:

Given that,

Charge, $q=1.4\ \mu C=1.4\times 10^{-6}\ C$

Force experienced by the charge, F = 0.59 N

We need to find the magnitude of charge density on either plate of the capacitor. Electric field on parallel plate capacitor is given by :

$E=\dfrac{\sigma}{\epsilon_o}$

$E=\dfrac{F}{q}$

$\dfrac{F}{q}=\dfrac{\sigma}{\epsilon_o}$

$\sigma=\dfrac{F.\epsilon_o}{q}$

$\sigma=\dfrac{0.59\times 8.85\times 10^{-12}}{1.4\times 10^{-6}}$

$\sigma=3.72\times 10^{-6}\ C/m^2$

So, the charge density on either plate of the capacitor is $3.72\times 10^{-6}\ C/m^2$ . Hence, this the required solution.

4 0

3 years ago