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otez555 [7]
4 years ago
6

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba

ll’s journey will gravity be the greatest force acting on the ball?
Physics
2 answers:
MakcuM [25]4 years ago
7 0
At the very top of the peak and on the way down
user100 [1]4 years ago
7 0
Hello There!

I'm assuming it is when it is at its highest point.

Hope This Helps You!
Good Luck :) 

- Hannah ❤
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A railroad track and a road cross at right angles. An observer stands on the road and watches an eastbound train traveling at 60
mamaluj [8]

Answer:

After 4 s of passing through the intersection, the train travels with 57.6 m/s

Solution:

As per the question:

Suppose the distance to the south of the crossing watching the east bound train be x = 70 m

Also, the east bound travels as a function of time and can be given as:

y(t) = 60t

Now,

To calculate the speed, z(t) of the train as it passes through the intersection:

Since, the road cross at right angles, thus by Pythagoras theorem:

z(t) = \sqrt{x^{2} + y(t)^{2}}

z(t) = \sqrt{70^{2} + 60t^{2}}

Now, differentiate the above eqn w.r.t 't':

\frac{dz(t)}{dt} = \frac{1}{2}.\frac{1}{sqrt{3600t^{2} + 4900}}\times 2t\times 3600

\frac{dz(t)}{dt} = \frac{1}{sqrt{3600t^{2} + 4900}}\times 3600t

For t = 4 s:

\frac{dz(4)}{dt} = \frac{1}{sqrt{3600\times 4^{2} + 4900}}\times 3600\times 4 = 57.6\ m/s

4 0
3 years ago
What influences the path that surface currents take?
Anastasy [175]
The answer is wind forces and Earth’s rotation
8 0
3 years ago
Read 2 more answers
Three students have been studying relative motion and decide to do an experiment to demonstrate their knowledge. The experiment
miskamm [114]

Answer with Explanation:

We are given that

Constant speed of Jane=12.6 m/s

a.When Fred can throw the ball 30  m/s

We have to find the angle relative to the horizontal when he throw the ball in order for Sue to see the ball travel vertically upward.

Let \theta be the angle .

Therefore,

30 cos\theta=12.6

cos\theta=\frac{12.6}{30}=0.42

\theta=cos^{-1}(0.42)=65.165^{\circ}

b.We have to find the height to which ball reach.

v^2-v^2_0=2aS

S=\frac{v^2-v^2_0}{2a}=\frac{0-(30 sin65.165)^2}{2(-9.81)}

S=37.78 m

7 0
3 years ago
How do scientists use the Doppler effect to understand the universe?
professor190 [17]
There's a very subtle thing going on here, one that could blow your mind.

Wherever we look in the universe, no matter what direction we look,
we see the light from distant galaxies arriving at our telescopes with
longer wavelengths than the light SHOULD have.

The only way we know of right now that can cause light waves to get
longer after they leave the source is motion of the source away from
the observer. The lengthening of the waves on account of that motion
is called the Doppler effect.  (The answer to the question is choice-c.)

But that may not be the only way that light waves can get stretched.  It's
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From that, we say the whole universe is expanding, and that right there is
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Now:  If ... say tomorrow ... a competent Physicist discovers another way
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theory along with it !


Now that our mind has been blown, come back down to Earth with me,
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It's true that when we look at distant galaxies, we do see their light
arriving in our telescopes with longer wavelengths than it should have.
And then we use the Doppler effect to calculate how fast that galaxy
is moving away from us.  That's all true.  Astronomers are doing it
every day.                                   I mean every night.

So here's the question for you to think about ... maybe even READ about:

When the light from a distant galaxy pours into our telescope, and we
look at it, and we measure its wavelength, and we find that the wavelength
is longer than it should be ... how do we know what it should be ? ? ?
6 0
3 years ago
Read 2 more answers
Which planet has the most extreme temperature variations
vichka [17]

Answer:

I believe Mercury has the most extreme temperatures in the solar system, ranging from -280?F at night to 800 degrees F during the day for parts of the surface.

Hope that helps! :)

5 0
3 years ago
Read 2 more answers
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