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kupik [55]
4 years ago
7

What effect does the vertical acceleration have on the horizontal velocity of the projectile?

Physics
1 answer:
KengaRu [80]4 years ago
3 0
Answer:
None, if air resistance is ignored.

Explanation:
At any instant, the projectile has vertical and horizontal components of velocity.
Vertical acceleration due to gravity affects the vertical velocity by accelerating the object toward the center of the earth, and by decreasing the upward vertical velocity.. 
The horizontal component of velocity makes the object travel horizontally as long as the projectile is airborne.
Thsi discussion assumes that air resistance is ignored.
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Which component is used to measure the current in a circuit
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Ammeter is used to measure the current in a circut 
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3 years ago
A student is watching a video in order to understand how convection in the mantle of the Earth occurs. The video shows rock risi
PSYCHO15rus [73]

Answer:

A

Explanation:

Because of the convectional currents

8 0
3 years ago
How many electrons does a neutral atom of sudium-25 have
horrorfan [7]

Answer:

Option A. 11

Explanation:

The atomic number of an element does not change.

Recall:

Atomic number = proton number

If the atom is neutral, then,

Proton number = electron number

Since the element is sodium, then, the atomic number of sodium–25 is 11.

Also, we were told to obtain the electrons of a neutral atom of sodium–25

Therefore,

Atomic number = proton number = 11

Since the atom is neutral,

Proton number = electron number = 11

8 0
3 years ago
On earth, you swing a simple pendulum in simple harmonic motion with a period of 1.6 seconds. what is the period of this same pe
polet [3.4K]
The period of a simple pendulum is given by
T= 2 \pi  \sqrt{ \frac{L}{g} }
where
L is the pendulum length
g is the acceleration of gravity

If we move the same pendulum from Earth to the Moon, its length L remains the same, while the acceleration of gravity g changes. So we can write the period of the pendulum on Earth as:
T_e= 2 \pi \sqrt{ \frac{L}{g_e} }
where g_e is the acceleration of gravity on Earth, while the period of the pendulum on the Moon is
T_m= 2 \pi \sqrt{ \frac{L}{g_m} }
where g_m is the acceleration of gravity on the Moon. 

If we do the ratio of the two periods, we get
\frac{T_m}{T_e} =  \sqrt{ \frac{g_e}{g_m} }
but the gravity acceleration on the Moon is 1/6 of the gravity acceleration on Earth, so we can write g_e = 6 g_m and we can rewrite the previous ratio as
\frac{T_m}{T_e} = \sqrt{ \frac{6 g_m}{g_m} }=  \sqrt{6}

so the period of the pendulum on the Moon is
T_m =  \sqrt{6}  T_e =  \sqrt{6} (1.6 s)=3.9 s
8 0
4 years ago
If an object falls from rest and lands 3.2 seconds later, how many<br> meters did it fall
DIA [1.3K]

Answer:

50.2 meters

Explanation:

When an object falls, it goes a distance d in time t according to the formula:

d=\frac{1}{2}*g*t^{2}

d is the distance in meter, g is the acceleration due to gravity with the value of 9.8m/s^{2} , t is the time in seconds

Therefore, d = \frac{1}{2}*9.8*(3.2)^{2}

d= 50.176 ≈ 50.2m

6 0
3 years ago
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