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ra1l [238]
3 years ago
15

You are on an airplane traveling with a constant velocity at an altitude of 20,000m. What is the acceleration of gravity at that

altitude? The earth's radius is 6.37 x 10^6m.. . A) 9.81 m/s^2. B) 9.78 m/s^2. C) 9.75 m/s^2. D) 9.72 m/s^2. E) 9.69 m/s^2.
Physics
2 answers:
-BARSIC- [3]3 years ago
3 0
The correct answer would be A.The acceleration of gravity is <span>9.81 m/s^2. This is calculated by using the equation:

a = GM/r</span>²

where G is the gravitational constant 6.6726 x 10-11N-m2/kg2, M is the mass of the planet (<span>5.9736E+24 kg) and r is the radius of the planet.
</span>
AleksAgata [21]3 years ago
3 0

Answer:

C) 9.75m/s^2

Explanation:

Acceleration of gravity is calculated with the following formula:

g=\frac{GM}{r^2}

Where G It is the universal gravitational constant

G=6.674x10^{-11}Nm^2/kg^2

and M is the mass of the earth:

M=5.972x10^{24} kg

r is the distance from the center of earth wich will be in this case the earth's radius plus the altitude of the airplane:

r=6.37x10^{6} m + 20000m=6.39x10^{6}m

thus, the acceleration g is:

g=\frac{(6.674x10^{-11}Nm^2/kg^2)(5.972x10^{24} kg)}{(6.39x10^{6}m)^2} =9.75m/s^2

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The needle of a compass will always lies along the magnetic field lines of the earth. 
A magnetic declination at a point on the earth’s surface equal to zero implies that 
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The presence of a current-carrying wire creates an additional <span>
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<span>
Where:</span>

B1 = magnetic field of the earth along the x-axis = 0.45 × 10 ⁻ ⁴ T

B2 = magnetic field due to the straight vertical wire along the y-axis

We can calculate for B2 using Amperes Law:

B2 = μ₀ i / [ 2 π R ]

B2 = [ 4π × 10 ⁻ ⁷ T • m / A ] ( 36 A ) / [ 2 π (0.21 m ) ] <span>
B2 = 5.97 × 10 ⁻ ⁵ T = 0.60 × 10 ⁻ ⁴ T </span>

The angle can be calculated using tan function:<span>
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θ = 53°

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The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak cu
Gemiola [76]

Answer:

6.66\cdot 10^{-12}T

Explanation:

The magnetic field produced by a current-carrying wire is given by

B=\frac{\mu_0 I}{2\pi r}

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\mu_0 is the vacuum permeability

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In this problem we have

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B=\frac{(4\pi \cdot 10^{-7} H/m)(4\cdot 10^{-8}A)}{2\pi (0.0012 m)}=6.66\cdot 10^{-12}T

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Juli2301 [7.4K]

Answer:

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Explanation:

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then when i put negative work it was right

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