The net force acting on the block is ~
So, the Answer in the boxes will be ~
The type of energy that depends on position is called
kinetic energy
Answer:
vb = 22.13 m/s
Explanation:
ma = 124 kg
mb = 13 kg
vi = 2.10 m/s
According to the property of conservation of momentum, and considering that, initially, both the astronaut and the bag moved together at 2.10 m/s:
The minimum final velocity of the bag, vb, the will keep the astronaut from drifting away forever occurs when va = 0:
The minimum final velocity of the bag is 22.13 m/s.
Given Information:
Diameter = d = 100 m
Required Information:
Period = T = ?
Answer:
Period = T = 14.2 seconds
Explanation:
We know that a station revolving at an angular velocity ω, have an acceleration given by
α = ω²r
Where ω is angular velocity and r is the radius of cylindrical space station.
Normal gravity means α = g = 9.8 m/s²
ω² = α/r
ω = √(α/r)
The radius is given by
r = d/2
r = 100/2
r = 50 m
ω = √(9.8/50)
ω = 0.4427 rad/sec
We also know that
ω = 2πf
f = ω/2π
f = 0.4427/2π
f = 0.0704 rev/sec
Finally time period is given by
T = 1/f
T = 1/0.0704
T = 14.2 sec
Therefore, the rotation period is 14.2 seconds.
