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3 years ago

Help please i need it

Mathematics

1 answer:

ValentinkaMS [17]3 years ago

5 0

9514 1404 393

Answer:

the shape is a trapezoid
use the area formula
48783 mm²

Step-by-step explanation:

The top and bottom edges are parallel, and the shape has 4 sides. That means it is a trapezoid. The area can be found using the formula for the area of a trapezoid:

A = 1/2(b1 +b2)h

A = 1/2(85 mm + 218 mm)(322 mm) = 1/2(303)(322) mm² = 48783 mm²

You might be interested in

Can anyone please help me solve it<br>11,12 (1)(2)(3),13 this is all

kondor19780726 [428]

Answer:

answer of 11

Step-by-step explanation:

given A=30°

R.H.S=2sinA cosA

=2 * sin30° * cos30°

$2 \times \frac{1}{2} \times \frac{ \sqrt{3} }{2}$

$= \frac{ \sqrt{3} }{2}$

=sin60°

sin 2*30°

=sin2A

L.H.S=R.H.S

8 0

3 years ago

Please help thank you

PtichkaEL [24]

Answer:

(d) y = -5/2x -3

Step-by-step explanation:

All of the offered choices are in slope-intercept form, so it makes sense to put the given equation in that form. Solving for y, we get ...

5x +2y = -4

2y = -5x -4 . . . . . subtract 5x

y = -5/2x -2 . . . . . divide by 2

The system of equations will have <em>no solution</em> if the equations are "inconsistent." That will be the case when the slope is the same, but the y-intercepts are different. That means you're looking for an answer of the form ...

y = -5/2x +c . . . . . . where c is not -2

This matches the last choice:

y = -5/2x -3

4 0

2 years ago

At a large Midwestern university, a simple random sample of 100 entering freshmen in 1993 found that 20 of the sampled freshmen

guajiro [1.7K]

Answer:

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

p1 -> 1993

20 out of 100, so:

$p_1 = \frac{20}{100} = 0.2$

$s_1 = \sqrt{\frac{0.2*0.8}{100}} = 0.04$

p2 -> 1997

10 out of 100, so:

$p_2 = \frac{10}{100} = 0.1$

$s_2 = \sqrt{\frac{0.1*0.9}{100}} = 0.03$

Distribution of p1 – p2:

$p = p_1 - p_2 = 0.2 - 0.1 = 0.1$

$s = \sqrt{s_1^2+s_2^2} = \sqrt{0.04^2 + 0.03^2} = 0.05$

Confidence interval:

$p \pm zs$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower bound of the interval is:

$p - zs = 0.1 - 1.645*0.05 = 0.01775
$

The upper bound of the interval is:

$p + zs = 0.1 + 1.645*0.05 = 0.18225
$

The 90% confidence interval for the difference of proportions is (0.01775,0.18225).

6 0

3 years ago

Find the values of x and y.

Ipatiy [6.2K]

Value of X and Y is 90 and 26 respectively.

3 0

3 years ago

What is the least common denominator of the fraction 2 over x plus the fraction x over x plus 1 plus the fraction x plus 1 over

Anna71 [15]

3x is the least common denominators because you need to be able to make sure all other denominators can go multiple into it. Since the rest are just x, the largest number of 3x would be the denominator you want.

5 0

3 years ago