Question

Bromine tends to form simple ions which have the electronic configuration of a noble gas. What is the electronic configuration of the noble gas which the bromide ion mimics?

Answer 1

Answer:

$Kr=1s^{2} 2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}$

Explanation:

The electronic configuration is defined as the setting or the arrangement of electrons in the shells of an atom. Generally, the noble gases do not react and thus show inertness. This property is due to 8 electrons in their outermost shell except for Helium. Bromine is a non-metal that has 35 electrons.

                       When Bromine atom gains an electron then becomes ion and called as bromide ion and thus bromide ion contains 36 electrons. Krypton is a noble gas that has 36 electrons and thus its electronic configuration is  $1s^{2} 2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}$.