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Kazeer [188]
2 years ago
9

In the following reaction, how many grams of nitroglycerin c3h5(no3)3 will decompose to give 25 grams of co2?4c3h5(no3)3(l) 12co

2(g) 6n2(g) 10h2o(g) o2(g)
Chemistry
1 answer:
Korolek [52]2 years ago
7 0
The balanced reaction that describes the decomposition of nitroglycerin to produce carbon dioxide, nitrogen, water and oxygen is expressed: <span>4c3h5(no3)3(l) = 12co2(g)+ 6n2(g) +10h2o(g) + o2(g). Hence for every 4 moles of nitroglycerin used, 12 moles of carbon dioxide is produced. When 25 grams of CO2 is produced, we convert this to mass and multiply by 4/12 and multiply again with the molar mass of nitroglycerin. The answer is 42.99 grams nitroglycerin.</span>
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6.) The bond between which two atoms is most polar?*
Feliz [49]

Answer:

O-H bond

Explanation:

Let us work out the electronegativity difference between the elements in each bond in order to decide which of them is most polar.

For the C-O bond

2.55 - 2.2 =0.35

For the F-F bond

3.98 - 3.98 = 0

For the O-H bond

3.44 - 2.2 = 1.24

For the N-H bond

3.04 - 2.2 = 0.84

The O-H bond has the highest electronegativity difference, hence it is he most polar bond.

4 0
2 years ago
A tank contains 90 kg of salt and 2000 L of water. Pure water enters a tank at the rate 6 L/min. The solution is mixed and drain
sashaice [31]

Answer:

a) 90 kg

b) 68.4 kg

c) 0 kg/L

Explanation:

Mass balance:

-w=\frac{dm}{dt}

w is the mass flow

m is the mass of salt

-v*C=\frac{dm}{dt}

v is the volume flow

C is the concentration

C=\frac{m}{V+(6-3)*L/min*t}

-v*\frac{m}{V+(6-3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{m}{2000L+(3)*L/min*t}=\frac{dm}{dt}

-3*L/min*\frac{dt}{2000L+(3)*L/min*t}=\frac{dm}{m}

-3*L/min*\int_{0}^{t}\frac{dt}{2000L+(3)*L/min*t}=\int_{90kg}^{m}\frac{dm}{m}

-[ln(2000L+3*L/min*t)-ln(2000L)]=ln(m)-ln(90kg)

-ln[(2000L+3*L/min*t)/2000L]=ln(m/90kg)

m=90kg*[2000L/(2000L+3*L/min*t)]

a) Initially: t=0

m=90kg*[2000L/(2000L+3*L/min*0)]=90kg

b) t=210 min (3.5 hr)

m=90kg*[2000L/(2000L+3*L/min*210min)]=68.4kg

c) If time trends to infinity the  division trends to 0 and, therefore, m trends to 0. So, the concentration at infinit time is 0 kg/L.

6 0
3 years ago
The chart below includes images of different structures found in animals or plants. For each structure, describe the smaller liv
Lady_Fox [76]
Gggfvmkjhgtfgjjhghhhhfddfgghhjjjjjjjj
5 0
2 years ago
"how many molecules of carbon dioxide exit your lungs when you exhale 5.00 × 10−2 mol of carbon dioxide, co2?"
IrinaVladis [17]
We are going to use Avogadro's constant to calculate how many molecules of

carbons dioxide exist in lungs:

when 1 mole of CO2 has 6.02 x 10^23 molecules, so how many molecules in

CO2 when the number of moles is 5 x 10^-2

number of molecules = moles of CO2 * Avogadro's number

                                     = 5 x 10^-2  * 6.02 x 10^23

                                     = 3 x 10^22 molecules 

∴ There are 3 x 10^22 molecules in CO2 exist in lungs 
5 0
3 years ago
Read 2 more answers
An aqueous solution has a volume of 2.0 L and contains 36.0g of glucose. If the Molar Mass of glucose is 180g/mol, what is the m
choli [55]

Answer:

moles = 36/180 = 0.2 moles

molarity = 0.2/2 = 0.1 mol/dm3

3 0
2 years ago
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