Answer : The solubility of this compound in g/L is 
.
Solution : Given,
Molar mass of 
= 114.945g/mole
The balanced equilibrium reaction is,
At equilibrium s s
The expression for solubility constant is,
![K_{sp}=[Mn^{2+}][CO^{2-}_3]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMn%5E%7B2%2B%7D%5D%5BCO%5E%7B2-%7D_3%5D)
Now put the given values in this expression, we get
The value of 's' is the molar concentration of manganese ion and carbonate ion.
Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.
Therefore, the solubility of this compound in g/L is .
Molarity of solution is defined as number of moles present in one liter solution. Mathematically, it is expressed as
Molarity =
Thus, if 1 mole of solute is present in 1 liter solution, molarity of solution is 1 M.
In present case, initial conc, of solution was 1.25 M.
∴ Number of moles of <span>co[h2o]6cl2 available initially = 1.25 mole, if the solution is 1 liter</span>
Answer: Either give off or gain electrons to make a total of 8
Answer:
B. Green solution density is 1.06 g/ml and blue solution density is 1.20 g/ml
Explanation:
Density is given as,
D = Mass / Volume
Red Solution,
D = 25 g / 25 mL
D = 1 g/mL
Green Solution,
D = 26.5 g / 25 mL
D = 1.06 g/mL
Yellow Solution,
D = 28.2 g / 25 mL
D = 1.128 g/mL
Blue Solution,
D = 30 g / 25 mL
D = 1.20 g/mL
Answer:about 2 grams of methane
Explanation:
idk just got this right
