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Travka [436]
2 years ago
12

Determine la cantidad aproximada de nitrato potásico (NaNO3) que habrá que mezclar con 150 g de agua para obtener una disolución

saturada a 10ºC.
A) 80 g
B) 40 g
C) 120 g
D) 160 g
Chemistry
1 answer:
hammer [34]2 years ago
4 0

Answer:

Determine the approximate amount of potassium nitrate (NaNO3) that must be mixed with 150 g of water to obtain a saturated solution at 10ºC.

A) 80 g

B) 40 g

C) 120 g

D) 160 g

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Balanced nuclear equation forces the alpha decay Po-210
Serjik [45]

Answer:

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

Explanation:

Your unbalanced nuclear equation is:

_{84}^{210}\text{Po} \longrightarrow \, _{x}^{y}\text{Z} + \, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

 84 = x + 2, so x =  84 - 2 =   82

210 = y + 4, so y = 210 - 4 = 206

Element 82 is lead, so the nuclear equation becomes

_{84}^{210}\text{Po} \longrightarrow \, _{82}^{206}\text{Pb} \, + \, _{2}^{4}\text{He}

8 0
3 years ago
True or false daltons atomic theory stated that matter is mostly empty space
Bas_tet [7]
The answer is false. Because Daltons theory stated that the Atom was a solid ball. 
3 0
3 years ago
What is the pH of a weak acid solution that has an [H+] of 2.1 x 10^-6 M?
yaroslaw [1]

Answer:

5.7 pH

Explanation:

To find pH when given [H+], you use this formula: pH = -log[H+]

-log * 2.1e-6 = 5.6778 = 5.7 pH

3 0
2 years ago
How do the test variables (independent variables) and outcome variables (dependent variables) in an experiment compare?
Sloan [31]

Answer/Explanation:

A) The independent(test) variable controls the dependent variable. A good way to think about this is that the independent variable has nothing that effects itself. The dependent variable is 'dependent' or reliant on the independent variable.

4 0
3 years ago
Read 2 more answers
What is the molarity of a solution in which 250 grams of NaCl are dissolved in 2.9 L of water?
Maksim231197 [3]

Answer:

About 1.48 M.

Explanation:

The formula for molarity is mol/L.

So firstly, you must find the amount of moles in 250 grams of NaCl.

I do this by using stoichiometry. First, I find how nany grams are in a single mole of NaCl. This is around 58.44 grams/mole. Now that I know this, I can now use a stoich table. (250 g NaCl * 1 mol NaCl / 58.44 g NaCl). I plug this into my calculator.

I get that 250 grams of NaCl is equal to about 4.28 moles.

Now I just plug into the formula!

4.28 moles/2.9 L = about 1.48

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3 0
2 years ago
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