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Travka [436]
2 years ago
12

Determine la cantidad aproximada de nitrato potásico (NaNO3) que habrá que mezclar con 150 g de agua para obtener una disolución

saturada a 10ºC.
A) 80 g
B) 40 g
C) 120 g
D) 160 g
Chemistry
1 answer:
hammer [34]2 years ago
4 0

Answer:

Determine the approximate amount of potassium nitrate (NaNO3) that must be mixed with 150 g of water to obtain a saturated solution at 10ºC.

A) 80 g

B) 40 g

C) 120 g

D) 160 g

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What makes alkali metals a family?​
navik [9.2K]

Answer:

The metals in this group are lithium, sodium, potassium, rubidium, cesium, and francium. The gas hydrogen is also put in this group because it shares similar reactivity with the alkali metals.

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3 0
3 years ago
What is power? (2 points)
damaskus [11]

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I believe

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Name the following alkane molecule:
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B
step-by-step explanation
7 0
2 years ago
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5. Balance the equation and state the limiting reagent in the following reaction:
mr Goodwill [35]

Answer:

5. 2 Al  3 Cl2 and 2 AlCl3

Cl2 is limiting

(It has the highest coefficients, but that's not always true. If they give you the number of grams for each make sure to work the math out)

6. C

(As the pressure increases there is less volume for the molecules to move around, therefore the molecules will be closer together, allowing for more collisions.)

7.  b

(if the temperature is increases so will the rate of the reaction. The increase in temperature will allow for the molecules to move at a faster rate, allowing for more collisions (reactions) between them.

8. d

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8 0
2 years ago
A sample of helium has a volume of 5 liters and a pressure of 699 mmHg. If the final volume is 5.7 Liters, its final temperature
malfutka [58]

Answer:

The initial temperature of helium was T1 = 232.23 K

Explanation:

Given data:

Initial volume V1 = 5 L

Initial pressure P1 = 699 mmHg

Final pressure P2 = 800 mmHg

Final volume V2 = 5.7 L

Final temperature T2= 303 K

Initial temperature T1 = ?

Solution:

Formula:

P1V1/T1 = P2V2/T2

T1 = T2 × P1V1/P2V2

T1 = 303 K × 699 mmHg × 5 L / 800 mmHg × 5.7 L

T1 = 1058985/ 4560

T1 = 232.23 K

initial temperature of helium was 232.23 k.

6 0
3 years ago
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