Answer:
6 Chickens
Step-by-step explanation:
Let H represent the number of horses and C represent the number of chickens. Since there are 32 legs altogether this means that on equation to use would be given by:
2C + 4 H = 32 (Eq. 1)
Another equation can be made from the fact that there are 11 heads or 11 animals altogether which can be written as:
C + H = 11 (Eq. 2)
From Eq. 2, solve for the number of chickens:
C + H = 11
C = 11 - H (Eq. 3)
Substituting Eq. 3 in Eq. 1, the number of horses can be determined:
2 C + 4 H = 32
2 ( 11 − H ) + 4 H = 32
22 − 2 H + 4 H = 32
2H = 32 − 22
2 H = 10
H = 5 Eq.4
Putting Eq.4 in Eq.1
2C + 4*5 = 32
2C = 32 - 20
2C = 12
C = 12/2
C = 6
The answer to this question would be: p+q+r = 2 + 17 + 39= 58
In this question, p q r is a prime number. Most of the prime number is an odd number. If p q r all odd number, it wouldn't be possible to get 73 since
odd x odd + odd= odd + odd = even
Since 73 is an odd number, it is clear that one of the p q r needs to be an even number.
There is only one odd prime number which is 2. If you put 2 in the r the result would be:
pq+2= 73
pq= 71
There will be no solution for pq since 71 is prime number. That mean 2 must be either p or q. Let say that 2 is p, then the equation would be: 2q + r= 73
The least possible value of p+q+r would be achieved by founding the highest q since its coefficient is 2 times r. Maximum q would be 73/2= 36.5 so you can try backward from that. Since q= 31, q=29, q=23 and q=19 wouldn't result in a prime number r, the least result would be q=17
r= 73-2q
r= 73- 2(17)
r= 73-34=39
p+q+r = 2 + 17 + 39= 58
Options A, B and E are the correct options.
Expenses are represented with negatives and income by positive.
For option E, 6x - 2.5x = 3.5x
Median= 3
Range= 5
Mode= 3
Mean= 4
Answer:
x = -3 and x = -3/2
Step-by-step explanation:
After writing down the polynomial, split it; put a line between 3x^2 and -18x. Look and 2x^3 + 3x^2 and -18x - 27 separately and factor them both:
p(x) = 2x^3 + 3x^2 <u>- 18x -27</u>
p(x) = x^2(2x+3) <u>-9(2x+3)</u>
Now notice how x^2 and -9 have the same factor (2x+3). That means x^2 and -9 can go together:
p(x) = (x^2 - 9)(2x+3)
Factor it once more because there's a difference of squares:
p(x) = (x+3)(x-3)(2x+3)
Now just plug in whatever makes the each bracket equal 0:
x = -3, x = 3, and x = -3/2
Those are your zeros.
