3 years ago

SCIENCE HELP! ASAP :)

Physics

1 answer:

Vinvika [58]3 years ago

6 0

I believe it's D. The centripetal force moves away from the center, but the marble stays there due to the string.

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PLEASE ASAP ILL GIVE BRAINLIEST.

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applied force

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any force where you push or pull is always applied force.

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2 years ago

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The position of the sun and the moon affect how high the tide is

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4. What is the acceleration of a plane that changes velocity from 75 m/s to

kompoz [17]

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3 years ago

Someone please help me!

beks73 [17]

Answer:

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3 years ago

A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha

slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity $\rho$ , the electric field $E$ , and the current density $J$ is given by

$\rho = \dfrac{E}{J}$

This equation can be solved for $J$ to get:

$J = \dfrac{E}{\rho}$

Since the current is $I = J\cdot A$

$I= J\cdot A = \dfrac{E}{\rho} \cdot A$

Now, for the tube of mercury $\rho = 9.84*10^{-7}\: \Omega \cdot m$ , $E = 23N/C$ , and the area is $A = \pi r^2 = \pi (1.0*10^{-3}m)^2 = 3.14*10^{-6}m^2$ ; therefore,

$I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2$

$\boxed{I = 73.39A.}$

Hence, the current through the mercury tube is 73.39A.

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3 years ago