Answer:
Explanation:
1 ) Force F = dp/ dt , p is momentum
= d/dt (mv)
= v dm/dt
Given dm/dt = 0.1 kg per second.
Force = v x 0.1
= .1 x .1
= .01 N
2 ) work done = force x displacement
Displacement in 1 s = 0. 1 m ( v = .1 m /s )
Work done in one second = .1 X .1
= .01 J
3 ) Velocity is constant so change in kinetic energy is due to additional mass .
Mass deposited in one second
= .1 g
Velocity = .1 m/s
Change in kinetic energy = 1/2 x .1 x .1 ²
= 5 x 10⁻⁴J
4 ) No , they are not the same. It is so because force has to do work against the frictional force offered by the surface on which sand is falling . So rise in kinetic energy is small as compared with work done by the force.
Answer : The value of is -166156 J and equilibrium composition should favor products at standard conditions.
Explanation :
Now we have to calculate the Gibbs free energy.
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = -249 kJ = -249000 J
= standard entropy = -278 J/K
T = temperature of reaction =
Now put all the given values in the above formula, we get:
- A reaction to be spontaneous when and reaction will be favored in the forward direction that means favored in products.
- A reaction to be non-spontaneous when and reaction will be favored in the backward direction that means favored in reactants.
As the value of is less than zero that means the reaction is spontaneous and reaction will be favored in the forward direction that means favored in products.
Hence, the value of is -166156 J and equilibrium composition should favor products at standard conditions.
Answer:
The maximum wavelength of light that could liberate electrons from the aluminum metal is 303.7 nm
Explanation:
Given;
wavelength of the UV light, λ = 248 nm = 248 x 10⁻⁹ m
maximum kinetic energy of the ejected electron, K.E = 0.92 eV
let the work function of the aluminum metal = Ф
Apply photoelectric equation:
E = K.E + Ф
Where;
Ф is the minimum energy needed to eject electron the aluminum metal
E is the energy of the incident light
The energy of the incident light is calculated as follows;
The work function of the aluminum metal is calculated as;
Ф = E - K.E
Ф = 8.02 x 10⁻¹⁹ - (0.92 x 1.602 x 10⁻¹⁹)
Ф = 8.02 x 10⁻¹⁹ J - 1.474 x 10⁻¹⁹ J
Ф = 6.546 x 10⁻¹⁹ J
The maximum wavelength of light that could liberate electrons from the aluminum metal is calculated as;
Answer:
a toy car speed is about 2.5 to 3.5 mph
Answer:
Atomic mass is the weighted average mass of an atom of an element based on the relative natural abundance of that element's isotopes. The mass number is a count of the total number of protons and neutrons in an atom's nucleus.