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svetlana [45]
3 years ago
8

Only two horizontal forces act on a 3.0 kg body that can move over a frictionless floor. one force is 9.0 n, acting due east, an

d the other is 9.2 n, acting 58° north of west. what is the magnitude of the body's acceleration?
Physics
1 answer:
Zolol [24]3 years ago
6 0
The first thing you should do for this case is to find the horizontal and vertical components of the forces acting on the body.
 We have then:
 Horizontal = 9-9.2cos (58) = 4.124742769 N.
 Vertical = 9.2sin (58) = 7.802042485 N
 Then, the resulting net force is:
 F = √ ((4.124742769) ^ 2 + (7.802042485) ^ 2) = 8.825268826 N
 Then by definition:
 F = m * a
 Clearing the acceleration:
 a = F / m
 a = (8.825268826) / (3.0) = 2.941756275 m / s ^ 2
 answer:
 The magnitude of the body's acceleration is
 2.941756275 m / s ^ 2
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Elevated water tanks are used in a municipal water distribution system to provide adequate pressure. Compute the height (h) of t
Lemur [1.5K]

Answer:

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a) For this exercise let's use Bernoulli's equation.

The subscript 1 is for the tank and the subscript for the building

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In general, the water tanks are open to the atmosphere, so P1 = Patm, also the tanks are very large so the speed of the water surface is very small v₁=0 and as they give us the precious static, this it is when the keys are closed so the output velocity is zero, v₂= 0. The height of the floors in a building is y₂ = 12 m

           

we substitute in Bernoulli's equation

         P_{atm} + 0 + ρ g h = P₂ + 0 + ρ g y₂

         h = \frac{(P_2 - P_{atm}) + \rho \ g \ y_2}{\rho \ g}

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indicate that the value of ΔP = 410 10³ Pa

       

we calculate

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           h_minimum = 28 m

maximums

           h_maximo = 620 103/1000 9.8

           h_maximum = 63.3 m

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Alpha particle consists of two protons and two neutron. It is a helium atom with mass number 4 and atomic number 2.

3 0
3 years ago
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