Answer:
To Put of a Fire.
Explanation:
incase an emergency happens, it's important to have a fir extingushier so the situation doesn't get worse and you can put out any possible fire's.
Answer:
D is the answer may be. I'm not sure.
Number of moles in the K2SO4 sample
= (16/1000)*1.04= 0.01664 mol
Number of moles in the Ba(NO3)2 sample
= (14.3/1000*0.880)= 0.01258 mol
Since the reaction is a 1:1 ratio between the two reactants, the limiting reagent is the one containing a smaller number of moles, namely Ba(NO3)2.
The molecular mass of BaSO4 is 137.3+(32.06+4*16.00)=233.4
Therefore the theoretical yield of Barium Sulphate is
233.4*0.01258=2.937 g
Actual yield = 2.60 g (given)
Therefore the percentage yield = 2.60/2.937=88.54%
Answer:
1. the limiting reagent is Barium Nitrate (Ba(NO3)2)
2. the theoretical yield is 2.94 g
3. the percentage yield is 88.5%
I apologize for the mistake previous to this update.
I think it would be B maybe
<h3>
![⇒c = \frac{f - 32}{1.8}](https://tex.z-dn.net/?f=%E2%87%92c%20%3D%20%20%5Cfrac%7Bf%20-%2032%7D%7B1.8%7D%20)
</h3><h3>
![⇒c = \frac{86 - 32}{1.8}](https://tex.z-dn.net/?f=%E2%87%92c%20%3D%20%20%5Cfrac%7B86%20-%2032%7D%7B1.8%7D%20)
</h3><h3>
![⇒c = \frac{54}{1.8}](https://tex.z-dn.net/?f=%E2%87%92c%20%3D%20%20%5Cfrac%7B54%7D%7B1.8%7D%20)
</h3><h3>
![⇒c = 30](https://tex.z-dn.net/?f=%E2%87%92c%20%3D%2030)
</h3>
<em>Hence</em><em>,</em><em> </em><em>84</em><em>°</em><em>F</em><em> </em><em>is</em><em> </em><em>30</em><em>°</em><em>C</em><em> </em><em>in</em><em> </em><em>Celsius</em><em>.</em><em>.</em>