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xeze [42]
3 years ago
14

What is the total mass of oxygen contained in 8.20g of benzoic acid (C6H5COOH)

Chemistry
1 answer:
VashaNatasha [74]3 years ago
4 0

Answer:

Mass of oxygen = 2.2 g

Explanation:

Given data:

Mass of benzoic acid= 8.20 g

Mass of oxygen= ?

Solution:

Molar mass of oxygen = 16×2 g/mol

Molar mass of C₆H₅COOH = 7×12 + 1×6 + 2×16

Molar mass of C₆H₅COOH = 84 + 6 + 32

Molar mass of C₆H₅COOH = 122g/mol

Mass of oxygen in 8.20 g of C₆H₅COOH :

Mass of oxygen = 32 g.mol⁻¹/122 g.mol⁻¹ × 8.20 g

Mass of oxygen = 2.2g

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A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask?
horsena [70]
A flask with a volume of 125.0 mL contains air with a density of 1.298 g/L. what is the mass of the air contained in the flask<span>The given are: </span>
<span><span>1.      </span>Mass = ?</span><span><span /></span>
<span><span>2.      </span>Density = 1298 g/L</span>
3.      Volume = 125mL to L
a. 125 ml x 0.001l/1ml = 0.125 L

<span>Formula and derivation: </span><span><span>
1.      </span>density = mass / volume</span> <span><span>
2.      mass </span>= density / volume</span>

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8 0
3 years ago
What is the concentration (M) of CH3OH in a solution prepared by dissolving 34.4 g of CH3OH in sufficient water to give exactly
bonufazy [111]

Answer:

4.67M

Explanation:

The concentration of methanol (CH3OH) can be calculated using the following:

Molarity (M) = number of moles(n)/volume(v)

However, mole is not given. It can be obtained by using:

Mole = mass / molar mass

Where; mass = 34.4g

Molar mass (MM) of CH3OH is:

= 12 + 1(3) + 16 + 1

= 12 + 3 + 17

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The volume needs to be converted to L by dividing by 1000

230mL = 230/1000

= 0.230L

Molarity = mol/volume

Molarity = 1.075/0.230

Molarity = 4.6739

Molarity = 4.67M

The concentration of CH3OH in solution is 4.67M

5 0
2 years ago
Thank uuuu so much!!!!!
kow [346]

Answer:

A. 0.83

Explanation:

Hopefully this helps!

7 0
3 years ago
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ivann1987 [24]
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4 0
2 years ago
Why is it better to allow the solvent front to move almost to the top of a paper strip rather than stopping it at the halfway po
m_a_m_a [10]

Answer:

To allow all the elements or compounds to separate complete.

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4 0
2 years ago
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