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vazorg [7]
3 years ago
15

Which of the following is NOT a benefit of cool down activities?

Physics
2 answers:
quester [9]3 years ago
5 0
B. Maximal lightheadedness
Rashid [163]3 years ago
5 0
B maximum lightheaded
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Answer:

Please refer to the figure.

Explanation:

The crucial point here is to calculate the enclosed current. If the current I is flowing through the whole cross-sectional area of the wire, the current density is

J = \frac{I}{\pi R^2}

The current density is constant for different parts of the wire. This idea is similar to that of the density of a glass of water is equal to the density of a whole bucket of water.

So,

J = \frac{I}{\pi R^2} = \frac{I_{enc}}{\pi r^2}\\I_{enc} = \frac{Ir^2}{R^2}

This enclosed current is now to be used in Ampere’s Law.

\mu_o I_{enc} = \int {B} \, dl

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As a result, the magnetic field is

B = \frac{\mu_0}{2\pi}\frac{Ir}{R^2}

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