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BaLLatris [955]
3 years ago
6

Acceleration increases over time once a force is applied to the object. Determine the acceleration at 3.5 sec? A) 3 m/s2 B) 6 m/

s2 C) 15 m/s2 D) 53 m/s2
Physics
2 answers:
borishaifa [10]3 years ago
6 0

Answer:

B) 6

Explanation:

I just got it wrong so u could get it right

Novay_Z [31]3 years ago
4 0

Answer: Acceleration does not increase over time once a force is applied to the object. It depends on the force and the object's mass. If those don't change, then the acceleration is constant.

Explanation:. F = M • a

We don't know either of those numbers, so we can't answer the question.

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What is the name of the force that is a combination of all forces that act on an object?
jarptica [38.1K]

Answer:

If the combination of all the forces acting on an object sums upto be zero, then the net force is known as <u>balanced force.</u>

If the combination of all the forces acting on an object is non-zero, then the net force is said to be <u>unbalanced force. </u>The unbalanced force causes the object change the state of rest or motion.

6 0
3 years ago
Plzzzz urgent <br><br><br>solve this​
Mariana [72]

Answer:

\large{ \tt{☄ \: EXPLANATION}} :

  • Before solving , You'll have to know - When an object starts from the state of rest , in this case , initial velocity ( u ) = 0

  • Notice that we're provided the time ( t ) in minutes. So , first thing we have to do is convert the minutes into seconds. It would be - Time ( t ) = 5 minutes = 5 × 60 sec = 300 sec [ 1 min = 60 sec ]

  • Here , We're provided - Initial velocity ( u ) = 0 , Final velocity ( v ) = 60 m / s , Time taken ( t ) = 300 seconds & We're asked to find out the acceleration ( a ) & distance covered by the jeep ( s ) .

\large{ \tt{♨ \:LET'S \: START}} :

  • Acceleration is defined as the rate of change of velocity. We know :

\large{ \boxed{ \tt{❁ \: ACCELERATION \: (a) =  \frac{FINAL \: VELOCITY(v) - INITIAL \: VELOCITY(u)}{TIME \: TAKEN \: ( \: t \: )}}}}

- Plug the values & then simplify !

\large{ \bf{↬a =  \frac{60 - 0}{300}  =  \frac{60}{300} =  \boxed{ \bold{ \bf{0.2 \: m {s}^{ - 2} }}} }}

  • The acceleration of the jeep is 0.2 m/s²

\large{ \tt{۵ \: AGAIN, \: USING\: SECOND \: EQUATION \: OF \: MOTION}} :

\boxed{ \large{ \bf{✾ \: s =  \frac{u + v}{2}  \times t}}}

- Plug the values & then simplify !

\large{ \bf{↦s =  \frac{0 + 60}{2}  \times 300 =  \boxed{ \bold{ \bf{9000 \: m}}}}}

  • The distance covered by the jeep is 9000 m .

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7 0
3 years ago
During which two phases would surfer’s most likely benefit
Strike441 [17]

Answer:

d

Explanation:

6 0
3 years ago
Read 2 more answers
An electron moving in the direction of the +x-axis enters a magnetic field. If the electron experiences a magnetic deflection in
algol13

Answer:

- z axis

Explanation:

The magnetic force is perpendicular to its speed and the direction of the magnetic field, its equation being

      F = q v x B

Where the bold indicates vectors, q  is a positive charge,

The way to use this equation is with the rule of the right hand, the thumb points in the direction of the velocity, the other fingers extended in the direction of the magnetic field and the palm is the direction of the force for a positive charge.

Let's apply this to our case the speed is on the x axis and the force in ex. negative Y axis, the other fingers point perpendicular to the sheet, but since the charge is negative the magnetic field enters the sheet, this would be the negative z axis

8 0
4 years ago
You slide a chair across a rough, horizontal surface. The chair's mass is 18.8 kg. The force you exert on the chair is 156 N dir
Luda [366]

Answer:

626.612 J

Explanation:

Work done by friction on the chair is given as

W-ΔEk = W'..................... Equation 1

Where W' = Work done by friction on the chair, W = Work done on the chair by me, Ek = change in Kinetic energy of the chair as a result of the slide.

From the question,

W = FdcosФ.............. Equation 2

ΔEk = 1/2m(v²-u²)................ Equation 3

Where F = Force applied on the chair, d = distance of slide, Ф = angle between the force and the horizontal, m = mass of the chair, v = final velocity of the chair, u = initial velocity of the chair

Substitute equation 2 and equation 3 into equation 1

W' = FdcosФ-1/2m(v²-u²)........................ Equation 4

Given: F = 156, d = 5 m, Ф = 26°, m = 18.8 kg, v = 3.1 m/s, u = 1.3 m/s

Substitute into equation 4

W' = 156×5×cos26°-1/2×18(3.1²-1.3²)

W' = 701.06-74.448

W' = 626.612 J.

Hence the work done by friction = 626.612 J

8 0
3 years ago
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