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3 years ago

PLEASE HELP ASAP!!!!

Physics

2 answers:

Sladkaya [172]3 years ago

6 0

Answer:12.5 W

Explanation:

work = force * distance

175 J = 25N * d

d = 7 meters ◄

power = work / time

P = 175J / 14s = 12.5 W ◄

amid [387]3 years ago

5 0

Answer:

The piano moved 7 meters.

The power generated was 12.5 Watts.

Explanation:

Work is defined as the force that is applied on a body to move it from one point to another.

When a net force is applied to the body or a system and this produces displacement, then that force is said to perform mechanical work.

In the International System of Units, work is measured in Joule. Joule is equivalent to Newton per meter.

The work is equal to the product of the force by the distance and by the cosine of the angle that exists between the direction of the force and the direction that travels the point or the object that moves:

Work = force*distance*cos (angle between the force and the displacement)

In this case, the angle between the force and the displacement is 0 degrees.

In this case, you know:

Work=175 Joule
Force=25 Newtons
Distance=?
Angle between the force and the displacement=0 degrees → cos (angle)=1

Replacing:

175 Joule=25 Newtons*distance*1

In this way, it is resolved to obtain:

$distance=\frac{175 Joule}{25 Newtons*1} =\frac{175 Newtons*meters}{25 Newtons*1}$

distance= 7 meters

The piano moved 7 meters.

Power is defined as the speed with which a job is performed. That is, power is the amount of work done for a unit of time:

$P=\frac{work}{time}$

Where P is the power developed by the force that performs the work and its unit of measure in the International System is the Watts (W), the unit of measure of work in the International System is Joule (J) and time during which the work is carried out, it has the unit of measure in the International System of seconds (s). So Watts is equivalent to $\frac{Joule}{second} =\frac{J}{s}$ .

So in this case:

$P=\frac{175 Joule}{14 seconds}$

P=12.5 $\frac{J}{s}$ =12.5 watts

The power generated was 12.5 Watts

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Does someone know how to do math with that equation

mestny [16]

Answer:

f = 5 cm

Explanation:

using the thin lens equation, given as follows:

$\frac{1}{f} = \frac{1}{d_{o}}+\frac{1}{d_{i}}\\$

where,

f = focal length = ?

do = the distance of object from lens = 20 cm

di = the distance of image from lens = 6.6667 cm

Therefore,

$\frac{1}{f} = \frac{1}{20\ cm}+\frac{1}{6.6667\ cm}\\\\\frac{1}{f} = 0.199999\ cm^{-1}\\\\f = \frac{1}{0.199999\ cm^{-1}}\\\\$

f = 5 cm

8 0

3 years ago

What are possible units for impulse? Check all that apply.

Neporo4naja [7]

Units of impulse: N • s, kg • meters per second

Explanation:

Impulse is defined in two ways:

Impulse is defined as the product between the force exerted in a collision and the duration of the collision:

$I=F\Delta t$

where

F is the force

$\Delta t$ is the time interval

Since the force is measured in Newtons (N) and the time is measured in seconds (s), the units for the impulse are

$[I] = [N][s]$

So,

N • s

Impulse is also defined as the change in momentum experienced by an object:

$I=\Delta p$

where the change in momentum is given by

$\Delta p = m\Delta v$

where m is the mass and $\Delta v$ is the change in velocity.

The mass is measured in kilograms (kg) while the change in velocity is measured in metres per second (m/s), therefore the units for impulse are

$[I]=[kg][m/s]$

so,

kg • meters per second

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

6 0

3 years ago

Read 2 more answers

The viewing screen in a double-slit experiment with monochromatic light. Fringe C is the central maximum. The fringe separation

makvit [3.9K]

Answer:

Part A:

a) If the wavelength of the light is decreased the fringe spacing Δy will decrease.

Part B:

b) If the spacing between the slits is decreased the fringe spacing Δy will increase.

Part C:

a) If the distance to the screen is decreased the fringe spacing will decrease.

Part D:

The dot in the center of fringe E is $920\ x\ 10^{-9} m$ farther from the left slit than from the right slit.

Explanation:

In the double-slit experiment there is a clear contrast between the dark and bright fringes, that indicate destructive and constructive interference respectively, in the central peak and then is less so at either side.

The position of bright fringes in the screen where the pattern is formed can be calculated with

$\vartriangle y =\frac{m \lambda L}{d}$

$m=0,\pm 1,\pm 2,\pm 3,.....$

m is the order number.
$\lambda$ is the wavelength of the monochromatic light.
L is the distance between the screen and the two slits.
d is the distance between the slits.

Part A: a) In the above equation for the position of bright fringes we can see that if the wavelength of the light $\lambda$ is decreased the overall effect will be that the fringes are going to be closer. That means that the fringe spacing Δy will decrease.

Part B: b) In the above equation for the position of bright fringes we can see that if the spacing between the slits d is decreased the fringes are going to be wider apart. That means the fringe spacing Δy will increase.
Part C: a) In the above equation we can see that if the distance to the screen L is decreased the fringes are going to be closer. That means the fringe spacing Δy will decrease.

Part D: We are told that the central maximum is the fringe C that corresponds with m=0. That means that fringe E corresponds with the order number m=2 if we consider it to be the second maximum at the rigth of the central one. To calculate how much farther from the left slit than from the right slit is a dot located at the center of the fringe E in the screen we use the condition for constructive interference. That says that the path length difference Δr between rays coming from the left and right slit must be $\vartriangle r=m \lambda$