4n-12=12-4n(If there is no solution, type in "no solution") n= Answer
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The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides
Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>
Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>
<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9
So, the area would be 9 times larger.
ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.
where "n" is the number of sides
Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>
Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>
<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9
So, the area would be 9 times larger.
ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation. So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.
Check the tree diagram in the picture.
Tom could pick Pants 1 (P1), then Sweater 1, 2 or 3. So 3 combinations
Similarly if we picked P2, P3, P4 or P5 we would have 3 combinations per each.
In total we have 5*3=15 different combinations.
Answer:15
Tom could pick Pants 1 (P1), then Sweater 1, 2 or 3. So 3 combinations
Similarly if we picked P2, P3, P4 or P5 we would have 3 combinations per each.
In total we have 5*3=15 different combinations.
Answer:15