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3 years ago

If n is an even number. (b) What type of number is n + 1?

Mathematics

1 answer:

NeTakaya3 years ago

5 0

Answer:

An odd number

Step-by-step explanation:

suppose n is 2.

If we add 1 into it, the answer will be 3, making it odd. same goes for any other even number if 1 is added in it

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Farmer Samantha has a cylindrical grain silo with a diameter of 12 feet and a height of 40 feet. The silo is filled with grain t

sammy [17]

Answer:

161,234 pounds of grain will remain in the silo

Step-by-step explanation:

In this question, we are to calculate the amount of grains that will be left in a silo if 20 cows feed on the content for 100 days.

Firstly, we need to calculate the amount of grains present in the silo.

This we can do by first calculating the volume of the silo. Since it is cylindrical in shape, we apply the formula for the volume of a cylinder.

Mathematically, the volume of a cylinder is

V = pi * r^2 * h

Here we have the r = D/2 = 12/2 = 6 feet and h = 40 feet. Plugging this , we have;

V = pi * 6^2 * 40 = 1440pi cubic feet

Now, per cubic feet, we have a weight of 48 pounds. The weight of grains thus present in the silo is thus;

1440pi * 28 = 1440 * pi * 48= 69,120pi pounds of grain

Let’s calculate what the cows would feast on. That would be 20 * 28 * 100 = 56,000 pounds of grains

Now we need to know what will remain. We just need to subtract what is consumed by the cows from we have inside the silo

What is inside the silo would be 69,120 * 22/7 = apprx 217,234 pounds

What will remain is thus 217,234 - 56,000 = 161,234 pounds of grain

3 0

3 years ago

Find the area of a circle with a radius of 6 <br> miles

AveGali [126]

Answer:

36π

Step-by-step explanation:

the formula of the area of the circle is πr^2

if the radius is 6, then its 6*6*π which is 36π

3 0

3 years ago

Read 2 more answers

Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the

Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million) Number of companies

25 up to 35 4

35 up to 45 19

45 up to 55 27

55 up to 65 16

65 up to 75 9

TOTAL 75

Let's find the probabilities first:

$P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}$

For 35 up to 45

$P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}$

For 45 up to 55

$P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}$

For 55 up to 65

$P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}$

For 65 up to 75

$P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}$

Chi-Square Table can be computed as follows:

Expense No of Probabilities(P) Expe $(O-E)^2$ $\dfrac{(O-E)^2}{E}$

compa cted E (n*p)

nies (O)

25-35 4 0.0612 75*0.0612 = 4.59 0.3481 0.0758

35-45 19 0.2218 75*0.2218 = 16.635 5.5932 0.3362

45-55 27 0.3568 75*0.3568 = 26.76 0.0576 0.021

55-65 16 0.2552 75*0.2552 = 19.14 9.8596 0.5151

65-75 9 0.0839 75*0.0839 = 6.2925 7.331 1.1650

$\sum \dfrac{(O-E)^2}{E}= 2.0492$

Using the Chi-square formula:

$X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square \ X^2 = 2.0942$

Null hypothesis:

$H_o: \text{The population of advertising expenses follows a normal distribution}$

Alternative hypothesis:

$H_a: \text{The population of advertising expenses does not follows a normal distribution}$

Assume that:

$\alpha = 0.02$

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from $X^2 = 11.667$

Decision rule: To reject $H_o \ if \ X^2$ test statistics is greater than $X^2$ tabulated.

Conclusion: Since $X^2 = 2.0942$ is less than critical value 11.667. Then we fail to reject $H_o$

6 0

3 years ago

10(2.1q -2) + (7.5q+18)

aliina [53]

Answer:

Simplify the expression.

28.5q−2

Step-by-step explanation:

i think this what you would like

6 0

3 years ago

Find one counter example to show that the conjecture is false. angle 1 and angle 2 are supplementary, so one of the angles is a

Mrac [35]

Answer:

B. m ∠ 1 = 90° and m ∠ 2 = 90°

Step-by-step explanation:

For most situations, the conjecture would probably be true, but there is one exception that makes this statement false.

When two right angles are supplementary, none of them is acute.

For an angle to be acute it needs to be lesser than 90°, and for a pair of angles to be supplementary they should add up to exactly 180°.

With a pair of right angles (90° each), their sum adds up to 180° but neither of them are acute.

Therefore, the answer is B. m ∠ 1 = 90° and m ∠ 2 = 90°

4 0

3 years ago