Phytoplankton populations are most abundant in the
1 answer:
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Answer:
1250 g=1.25 Kg
Explanation:
We are given that Jason has five fishes of equally massed lead fish weights.
Weigh of each fish =250 grams
We have to find the value of total mass of the five lead fishing weights
Total number of fishes=5
In order to find the total mass we will use unitary method
Total mass is obtained by multiplying the total number of fishes with weight of one fish
Total mass=
Total mass of five fishes=1250 g
1 kg =1000g
Then 1250 g=
Hence, total mass of five lead fishing weights=1250 g=1.25 Kg