Answer:
Q = 30 calories
Explanation:
We have,
The specific heat of ice is 0.5 calories/gram.
The heat require to raise the temperature is given by :
m = 60 grams, c = 0.5 calories/gram °C, 
So,
So, 30 calories of heat is required to raise the temperature by 1 C.
The answer is B that is sound wave. Sound wave required a medium to travel.
Mechanical wave is not capable of transfer its energy through vacuum . It required a medium to travel and sound wave is an example of mechanical wave that required a medium to travel.
So, All other wave that are listed here doesn't required a medium to travel, among all only sound wave requires a medium to travel.
Answer: 2205 lb/m^3
Explanation:
- 1g = 0.002205lb
- 1cm^3 = 1x10^-6m^3
Convert: (1g/cm^3)*(0.002205lb/g)*(1cm^3/1x10^-6m^3) = 2205 lb/m^3
Answer:
1 = Q = 7315 j
2 =Q = -21937.5 j
Explanation:
Given data:
Mass of water = 50 g
Initial temperature = 20°C
Final temperature = 55°C
Energy required to change the temperature = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water is 4.18 j/g.°C.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 55°C - 20°C
ΔT = 35°C
Q = 50 g× 4.18 j/g.°C×35°C
Q = 7315 j
Q 2:
Given data:
Mass of metal = 100 g
Initial temperature = 1000°C
Final temperature = 25°C
Energy released = ?
Specific heat capacity = 0.225 j/g.°C
Solution:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 25°C - 1000°C
ΔT = -975°C
Now we will put the values in formula.
Q = 100 g × 0.225 j/g.°C × -975°C
Q = -21937.5 j
Negative sign show that energy is released.
Buoyancy is a force that acts on objects that are placed in a fluid is the correct answer
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