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stira [4]
3 years ago
14

What is the average atomic mass of titanium

Chemistry
1 answer:
Vikki [24]3 years ago
7 0

47.867 u ± 0.001 u

I am sure but does average matter because all ik is that thats the atomic mass


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The specific heat of ice is 0.5 calories/gram.
dsp73

Answer:

Q = 30 calories

Explanation:

We have,

The specific heat of ice is 0.5 calories/gram.

The heat require to raise the temperature is given by :

Q=mc\Delta T

m = 60 grams, c = 0.5 calories/gram °C, \Delta T=1\ C

So,

Q=60\times 0.5\times 1\\\\Q=30\ \text{calories}

So, 30 calories of heat is required to raise the temperature by 1 C.

4 0
3 years ago
Which of these waves requires a medium to travel through?
77julia77 [94]

The answer is B that is sound wave. Sound wave required a medium to travel.

Mechanical wave is not capable of transfer its energy through vacuum . It required a medium to travel and sound wave is an example of mechanical wave that required a medium to travel.

So, All other wave that are listed here doesn't required a medium to travel, among all only sound wave requires a medium to travel.

6 0
3 years ago
Read 2 more answers
The density of water is 1.00g/cm3. Express this density in lb/m3​
Ira Lisetskai [31]

Answer:  2205 lb/m^3

Explanation:  

  • 1g = 0.002205lb
  • 1cm^3 = 1x10^-6m^3

Convert:  (1g/cm^3)*(0.002205lb/g)*(1cm^3/1x10^-6m^3) = 2205 lb/m^3

           

4 0
3 years ago
Please someone help meeeeee!!!
Lorico [155]

Answer:

1 = Q =  7315 j

2 =Q =  -21937.5 j

Explanation:

Given data:

Mass of water = 50 g

Initial temperature = 20°C

Final temperature = 55°C

Energy required to change the temperature = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 55°C - 20°C

ΔT = 35°C

Q = 50 g× 4.18 j/g.°C×35°C

Q =  7315 j

Q 2:

Given data:

Mass of metal = 100 g

Initial temperature = 1000°C

Final temperature = 25°C

Energy released = ?

Specific heat capacity = 0.225 j/g.°C

Solution:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 25°C - 1000°C

ΔT = -975°C

Now we will put the values in formula.

Q = 100 g × 0.225 j/g.°C × -975°C

Q =  -21937.5 j

Negative sign show that energy is released.

7 0
3 years ago
Which of the statements below about buoyancy is true?
Fynjy0 [20]
Buoyancy is a force that acts on objects that are placed in a fluid is the correct answer
Let me know if I agit it!
3 0
4 years ago
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