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lukranit [14]
4 years ago
13

3. The largest asteroid in the solar system is 1 Ceres. It has a mass of 9.3835

Physics
1 answer:
Ira Lisetskai [31]4 years ago
3 0

Answer:

2.8351×10^7 N/kg

Explanation:

We know that,

W = mg -------(1)

where W = weight, m = mass, g = gravitational acceleration

Also from Newton's law of gravitation we know that,

F = GMm/r²

Where,

F = gravitational force,

G = universal gravitational constant

M,m = masses of object under gravitational influence

r = distance between the two center of masses.

Here we get

F = (Gm/r²)M -------(2)

From 1 and 2

The acceleration due to gravity = gravitational field intensity

So if you consider the gravitational field intensity at the surface of the asteroid,it is equal to the acceleration due to gravity at the same place.

So we get,

g = (6.67×10^-11)×9.3835×10^20/(47²) = 2.8351×10^7 N/kg

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"A uniform cylinder of mass M and radius R is rolling without slipping. The velocity of its center of mass is v. What is the cyl
Goshia [24]

Answer:

Explanation:

Given

mass of cylinder is M

radius R

velocity of center of mass is v

As there is no slipping therefore cylinder will rotate as well as translate

Moment of inertia of cylinder I=\frac{MR^2}{2}

Kinetic Energy of cylinder K.E.=\frac{1}{2}Mv^2

Rotational energy R.E.=\frac{1}{2}I\omega ^2

for rolling

v=\omega \times r

where \omega =angular\ velocity\ of\ cylinder

R.E.=\frac{1}{2}\times \frac{MR^2}{2}\times (\frac{v}{R})^2=\frac{1}{4}Mv^2

Total kinetic Energy =\frac{1}{2}Mv^2+\frac{1}{4}Mv^2=\frac{3}{4}Mv^2

6 0
3 years ago
Trace the path of a ray emitted from the tip of the object toward the focal point of the mirror and then the reflected ray that
Crazy boy [7]

Answer: find the attached files for the answer

Explanation:

The reflected ray appears to have originated from the focal point. We should actually draw a vector from the focal point through the point where the incident ray hits the mirror but we shorten the vector so that its starting point is on the mirror, without changing its angle.

Please find the attached files for the solution

5 0
4 years ago
Tom Cruise jumped from one building to other building while filming the roof chase scene in Mission: Impossible - Fallout. He di
OLga [1]

Answer:

v_0=9.9\ m.s^{-1}

Explanation:

Given:

  • angle of launch of projectile from horizontal, \theta=15^{\circ}
  • range of projectile, R=5\ m

<u>We have formula  for the range of projectile:</u>

R=\frac{v_0^2\times sin\ 2\theta}{g}

putting the respective values

5=\frac{v_0^2\times sin\ 30^{\circ}}{9.8}

v_0=9.9\ m.s^{-1} is the velocity with which Tom should jump to land on the other roof.

3 0
3 years ago
is it possible to breed a black haired long tailed retriever? If so, what percentage is possible? PLEASE answer the corrects ans
Pachacha [2.7K]

Answer: it can be considered a genetic mutation with a history of a Golden Retriever in their blood but it is very rare. and there our some black retrievers you can buy too. i hope i helped

Explanation:

6 0
2 years ago
Read 2 more answers
HELP ME PLEASE!!!!!!!!!
Stolb23 [73]

As per the given Figure attached here we know that both charges q1 and q2 will apply same force on charge q3 and hence the resultant force due to both charges will be along Y axis vertically upwards

So here we know that

F = \frac{kq_1q_3}{d_{13}^2}

now from the above equation

F = \frac{(9\times 10^9)(2\times 10^{-6})(4 \times 10^{-6})}{0.5^2}

F = 0.288 N

so both of the charges will apply 0.288 N force on q3 charge along the line joining them

now the net force due to vector sum is given by

F_{net} = 2Fcos\theta

here we know that angle is

\theta = 37 degree

now we have

F_{net} = 2\times 0.288 cos37

F_{net} = 0.46 N

so net force on q3 is 0.46 N vertically upwards along +Y axis

6 0
3 years ago
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