Question

Young's double slit experiment is one of the quintessential experiments in physics. The availability of low cost lasers in recent years allows us to perform the double slit experiment rather easily in class. Your professor shines a green laser (564 nm) on a double slit with a separation of 0.108 mm. The diffraction pattern shines on the classroom wall 4.0 m away. Calculate the fringe separation between the fourth order and central fringe.

Answer 1

Answer:

Fringe width = 21 mm

Explanation:

Fringe width is given by the formula

$\beta = \frac{\Lambda L}{d}$

here we know that

$\Lambda = 564 nm$

L = 4.0 m

d = 0.108 mm

now from above formula we will have

$\beta = \frac{(564 \times 10^{-9})(4.0 m)}{0.108\times 10^{-3}}$

$\beta = 0.021 meter$

so fringe width on the wall will be 21 mm