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olchik [2.2K]
4 years ago
7

How much voltage must be applied across a 0.20 Ω wire in order to create a 30 A current? (Please show work for it too)

Physics
2 answers:
tester [92]4 years ago
7 0

Answer:

6 V

Explanation:

By ohm's law :

V = IR

V = 0.2 × 30 = 6 V

fredd [130]4 years ago
7 0

Answer:

V=6V

Explanation:

Use the equation I=V/R and solve for V then use V=IR plug in the numbers.

V=IR

V=30(0.2)

V=6V

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A solenoid with 400 turns has a radius of 0.040 m and is 40 cm long. If this solenoid carries a current of 12 A, what is the mag
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Answer:

The magnitude of the magnetic field inside the solenoid is 1.5 × 10⁻²T

Explanation:

Given that,

Length = 40 cm

Radius = 0.040 cm

Number of turns = 400

Current = 12 A

We need to calculate the magnetic field

Using formula of magnetic field inside the solenoid

B =\mu nIB =\mu\dfrac{N}{l}I

Where,\dfrac{N}{l}=Number of turns per unit length

I = current

B = magnetic field

Put the value into the formula

B =4\pi\times10^{-7}\times\dfrac{400}{40\times10^{-2}}\times12B = 1.5\times10^{-2}\ T

Hence, The magnitude of the magnetic field inside the solenoid is 1.5 × 10⁻²T

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3 years ago
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Which is an example of a chemical change?

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