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Black_prince [1.1K]
3 years ago
10

How much heat is absorbed by a 67g iron skillet when its temperature rises from 8C to 94C? ___ Joules

Physics
1 answer:
Katen [24]3 years ago
3 0
I googled the specific heat capacity for iron so it might be off to the value you might have used, bit it should be close.

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Example 3 :
kherson [118]

The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.

<h3>How to determine the friction factor</h3>

Using the formula

μ = viscosity = 0. 06 Pas

d =  diameter = 120mm = 0. 12m

V =  velocity = 1m/s and 3m/s

ρ = density = 0.9

a. Velocity = 1m/s

friction factor = 0. 52 × \frac{0. 06}{0. 12* 1* 0. 9}

friction factor = 0. 52 × \frac{0. 06}{0. 108}

friction factor = 0. 52 × 0. 55

friction factor = 0. 289

b. When V = 3mls

Friction factor = 0. 52 × \frac{0. 06}{0. 12 * 3* 0. 9}

Friction factor = 0. 52 × \frac{0. 06}{0. 324}

Friction factor = 0. 52 × 0. 185

Friction factor = 0.096

Loss When V = 1m/s

Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter

Head loss = 0. 289 × \frac{1}{2*6. 6743 * 10^-11} × \frac{1^2}{0. 120} × \frac{1}{100}

Head loss =  1. 80 × 10^8

Head loss When V = 3m/s

Head loss = 0. 096 × \frac{1}{1. 334 *10^-10} × \frac{3^2}{0. 120} × \frac{1}{100}

Head loss = 5. 3× 10^8

Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss  when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.

Learn more about friction here:

brainly.com/question/24338873

#SPJ1

4 0
2 years ago
A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t
Serga [27]

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

Rating= 250 A-h

a. Total charge:

Rating=Q/t\\Q=Rating.t\\

Suppose t=1h

Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec

We konw that Ampere=\frac{Coulomb}{sec}, replacing:

Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A

Maximum current provided by the battery for 37 minutes could be 405.405 A

4 0
3 years ago
Write atleast name of five devices which work under the principles of physics
Colt1911 [192]
You could say almost anything.
For example:
phones,
cars,
computers,
clocks,
hydraulics,
bicycles,
the hadron collider,
Planes,
and so on.
3 0
3 years ago
Read 2 more answers
An electromagnet is created using a battery, an insulated copper wire and an iron nail. The wire is wrapped around the nail 20 t
Molodets [167]
I think adding more loops would strengthen it
4 0
3 years ago
1. What is the kinetic energy of a frog that has mass of 13kg and can hop<br> 9m/s? *
emmasim [6.3K]

Answer:526.6J

Explanation:I did a test

8 0
3 years ago
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