8. If the mass of a balloon is 300 kg and the lift force provided by the atmosphere is 3300 N, what

Physics

1 answer:

zmey [24]2 years ago

3 0

Answer:

Toward the north, 300 N

Explanation:

Consider the upward direction as positive and downward direction as negative.

Given:

Mass of the balloon is, $m=300\ kg$

Lift force on the balloon in the upward direction is, $F_L=3300\ N$

Take acceleration due to gravity as 10 N/kg.

Now, weight of the balloon acting downward is given as the product of its mass and acceleration due to gravity. Therefore,

Weight is, $W=mg=(300\ kg)(10\ N/kg)=-3000\ N$

Now, net force is given as the vector sum of both the forces.

$F_{net}=F_L+W\\F_{net}=3300-3000=300\ N(\textrm{Upward direction})$

The upward direction is the direction of North. So, the net force acting on the balloon is 300 N towards North.

You might be interested in

For a molecule of O2 at room temperature (300 K), calculate the average angular velocity for rotations about the x or y axes. Th

Ksivusya [100]

Answer: 6.65 rad/s

Explanation:

Firstly, we need to know that according the kinetic theory of gases, the average kinetic energy $KE$ of a molecule with $i$ degrees of freedom is:

$KE=\frac{i}{2}kT$ (1)

Where:

$i=5$ because oxigen is a diatomic molecule and has 5 degrees of freedom

$k=1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K}$ is the Boltzman constant

$T=300 K$ is the temperature

Then:

$KE=\frac{5}{2}(1.38064852 (10)^{-23} \frac{m^{2}kg}{s^{2}K})(300 K)$ (2)

$KE=1.035 (10)^{-20} \frac{m^{2}kg}{s^{2}}$ (3) With this value of average kinetic energy we can find the average angular velocity, with the following equation: