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slava [35]
3 years ago
6

8. If the mass of a balloon is 300 kg and the lift force provided by the atmosphere is 3300 N, what

Physics
1 answer:
zmey [24]3 years ago
3 0

Answer:

Toward the north, 300 N

Explanation:

Consider the upward direction as positive and downward direction as negative.

Given:

Mass of the balloon is, m=300\ kg

Lift force on the balloon in the upward direction is, F_L=3300\ N

Take acceleration due to gravity as 10 N/kg.

Now, weight of the balloon acting downward is given as the product of its mass and acceleration due to gravity. Therefore,

Weight is, W=mg=(300\ kg)(10\ N/kg)=-3000\ N

Now, net force is given as the vector sum of both the forces.

F_{net}=F_L+W\\F_{net}=3300-3000=300\ N(\textrm{Upward direction})

The upward direction is the direction of North. So, the net force acting on the balloon is 300 N towards North.

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Due to the resistance of air, a drag force acts on a falling body (parachute) to slow down its motion. Without air resistance, or drag, objects would continue to increase speed until they hit the ground. The larger the object, the greater its air resistance. Parachutes use a large canopy to increase air resistance. Also, Once the parachute is opened, the air resistance overwhelms the downward force of gravity. The net force and the acceleration on the falling skydiver is upward. An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down. Sorry if not helpful.

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Which statement best defines work? (2 points) Group of answer choices
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In the diagram, 91, 92, and q3 are in a straight line. Each of these particles has a charge of -2.35 x 10-6 C. Particles q₁ and
Strike441 [17]

The net force on particle q₃ is  6.2128125 N.

<h3>What is electrostatic force?</h3>

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/d²

where k = 9 x 10⁹ N.m²/C²

Given is the diagram in which each of the particles has a charge of -2.35 x 10⁻⁶ C. Particles q₁ and q₂ are separated by 0.100 m and particles q₂ and q₃ are separated by 0.100 m.

Force acting on q₃ due to q₁

F₃₁  = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1)²

F₃₁ = 4.97025 N(in right direction)

Force acting on q₃ due to q₂

F₃₂ = 9 x 10⁹ x (-2.35 x 10⁻⁶)²/(0.1+0.1)²

F₃₂ = 1.2425 N (in right direction)

Net force acting on particle q₃ is

F₃ = F₃₁ +F₃₂

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Thus the net force on a charged particle is  6.2128125 N to the right.

Learn more about electrostatic force.

brainly.com/question/9774180

#SPJ1

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