Answer:
ignore the bully ,tell the bully to stop,make a joke or laugh with the bully,stick with friend,know how to get out of the bullying situation
Explanation:
Hello Micu212006
Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
</span><span>
Answer: True
Hope This Helps!
-Chris </span>
Answer: Some of the thing that are important for clouds to form are: Moisture - There must be sufficient water vapor in the air for a cloud to form. Cooling air - The air temperature must decrease enough for water vapor to condense
Explanation:
Answer:
The thickness is 
Explanation:
From the question we are told that
The wavelength is 
The first order of the dark fringe is 
The second order of dark fringe considered is 
Generally the condition for destructive interference is mathematically represented as

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe
So the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

=> 
=> 
=> 
Angstrom = 10^-10 m
for nucleus size are used fermi (femtometer 10^-15 m )