a) The polynomial in expanded form is
.
b) The slant asymptote is represented by the linear function is
.
c) There is a discontinuity at
with a slant asymptote.
a) In this question we are going to use the Factor Theorem, which establishes that polynomial are the result of products of binomials of the form
, where
is the i-th root of the polynomial and the grade is equal to the quantity of roots. Therefore, the polynomial
has the following form:

And the expanded form is obtained by some algebraic handling:



(1)
The polynomial in expanded form is
.
b) In this question we divide the polynomial found in a) (in factor form) by the polynomial
(also in factor form). That is:

(2)
The slant asymptote is defined by linear function, whose slope (
) and intercept (
) are determined by the following expressions:
(3)
(4)
If
, then the equation of the slant asymptote is:







The slant asymptote is represented by the linear function is
.
c) The number of discontinuities in rational functions is equal to the number of binomials in the denominator, which was determined in b). Hence, we have a discontinuity at
with a slant asymptote.
We kindly invite to check this question on asymptotes: brainly.com/question/4084552
Answer: Surface area= 54
Step-by-step explanation:
To find the surface area of a cube you do 6 times s^2
S is the side length. In this case that is 3 cm. S^2 is 9
So now you do 6 times 9, and that is 54.
So, the surface area is 54.
This is a proportion problem because the problem stated that the two team pennants are similar.
Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base = 6 in ; length = x ?
9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x
The length of the side of the smaller pennant is 3 inches.
Answer:
k = -10/7 and k = -3
Step-by-step explanation:
Given: <em>y</em> = <em>kx</em> + 2
where k is the slope of line and 2 is y-intercept.
∵ line <em>y</em> = <em>kx </em>+ 2 is passing through point <em>P</em> (-7, 12), ∴ <em>x</em> = -7 and <em>y </em>= 12
Now substituting the value of x and y in above equation,
<em>y </em>= <em>kx</em> + 2
12 =<em> k</em>(-7) + 2
-7<em>k</em> = 12 - 2
- 7<em>k</em> = 10

In the same way, ∵ line <em>y</em> = <em>kx </em>+ 2 is passing through point <em>P</em> (3, -7), ∴ <em>x</em> = 3 and <em>y </em>= -7
<em>y </em>= <em>kx</em> + 2
Now substituting the value of x and y in above equation,
-7 =<em> k</em>(3) + 2
<em>3k</em> = -7 - 2
<em>3k</em> = - 9
<em>k</em> = -3