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3 years ago

8

Ursula took out an unsubsidized Stafford loan to help pay for her first of her four years at college. The loan had a principal o

f $6,400, an interest rate of 6.9% compounded monthly. After college, Ursula started making monthly payments over a 10 year period on her loan. What percentage of the total cost of the loan is the finance charge?
a.
45.25%
b.
27.91%
c.
43.50%
d.
82.66%

2 answers:

Leokris [45]3 years ago

6 0

Answer:

a.

45.25%

Step-by-step explanation:

goblinko [34]3 years ago

3 0

The answer to the Ursula question is a - 45.25

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ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports

iVinArrow [24]

Answer:

He have <u>15</u> action games and <u>24</u> sports games.

Step-by-step explanation:

Given:

Ryan has a mix of action and sports games for a total of 39 video games his action collection is three more than half his sports collection.

Now, to find the number of action games and sports games.

Let the sports games be $x.$

As, given his action collection is three more than half his sports collection.

Thus, the action games = $3+\frac{x}{2}$ .

Total number of video games = 39.

So, we set an equation to get the number of action games and sports games:

$x+(3+\frac{x}{2})=39$

$x+3+\frac{x}{2} =39$

<em>Subtracting both sides by 3 we get:</em>

$x+\frac{x}{2} =36$

$\frac{2x+x}{2}=36$

$\frac{3x}{2} =36$

<em>Multiplying both sides by 2 we get:</em>

$3x=72$

<em>Dividing both sides by 3 we get:</em>

$x=24.$

<u>The sports games he have = 24.</u>

Now, to get the action games we substitute the value of $x$ :

$3+\frac{x}{2}$

= $3+\frac{24}{2}$

= $3+12$

= $15.$

<u>The action games he have = 15.</u>

Therefore, he have 15 action games and 24 sports games.

6 0

3 years ago

5x+2y=-3;x+5y=4<br>plz answer me

Alex17521 [72]

Answer:

x = -1 and y = 1

Step-by-step explanation:

5x + 2y = -3 . . . . . . . (i)

x + 5y = 4 . . . . . . . (ii)

Finding x in terms of y from eq. (ii) :-

x + 5y = 4

x = 4 - 5y

Placing this value of x in eq. (i) :-

5(4 - 5y) + 2y = -3

20 - 25y + 2y = -3

-23y = - 23

<u>y = 1</u>

Placing the value of y in eq. (i)

5x + 2(1) = -3

5x + 2 = -3

5x = - 5

<u>x = -1</u>

7 0

3 years ago

Read 2 more answers

What is the area of this irregular shape and how do I work it out?

Brilliant_brown [7]

Answer:

17cm²

Step-by-step explanation:

i hope it's helpful

7 0

2 years ago

Any body, Waiting for answer

mart [117]

The maximum height of the rocket is 43.89 feet

<h3>How to write the function</h3>

The general function is given as:

h(t) = -16t^2 + vt + h

The initial velocity is

v = 53

So, we have:

h(t) = -16t^2 + 53t + h

The initial height is

h = 0

So, we have:

h(t) = -16t^2 + 53t

Hence, the function of the height is h(t) = -16t^2 + 53t

<h3>The maximum height of the rocket</h3>

In (a), we have:

h(t) = -16t^2 + 53t

Differentiate the function

h'(t) = -32t + 53

Set to 0

-32t + 53 = 0

This gives

-32t = -53

Divide by -32

t = 1.65625

Substitute t = 1.65625 in h(t) = -16t^2 + 53t

h(1.65625) = -16 * 1.65625^2 + 53 * 1.65625

Evaluate

h(1.65625) = 43.890625

Approximate

h(1.65625) = 43.89

Hence, the maximum height of the rocket is 43.89 feet

<h3>Time to hit the ground</h3>

In (a), we have

h(t) = -16t^2 + 53t

Set to 0

-16t^2 + 53t = 0

Divide through by -t

16t - 53 = 0

Add 53 to both sides

16t = 53

Divide by 16

t = 3.3125

Hence, the time to hit the ground is 3.3125 seconds

<h3>The graph of the function h(t)</h3>

See attachment for the graph of the function h(t)

Read more about height functions at:

brainly.com/question/12446886

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1 year ago

Graph a parabola whose x-intercepts are at x=-3 and x=5 and whose minimum value is y=-4

docker41 [41]

Answer:

(See explanation for further details)

Step-by-step explanation:

The standard equation of the parabola is:

$y + 4 = C \cdot (x-k)^{2}$

The formula is now expanded into a the form of a second-order polynomial:

$y + 4 = C\cdot x^{2} -2\cdot C\cdot k \cdot x +C\cdot k^{2}$

$y = C\cdot x^{2} - (2\cdot C \cdot k) \cdot x + (C\cdot k^{2}-4)$

The general equation of the second-order polynomial is:

$x = \frac{2\cdot C \cdot k \pm \sqrt{4\cdot C^{2}\cdot k^{2}-4\cdot C\cdot (C\cdot k^{2}-4)}}{2\cdot C}$

$x = k \pm \frac{\sqrt{C^{2}\cdot k^{2}-C^{2}\cdot k^{2}+4\cdot C}}{C}$

$x = k \pm 2\cdot \frac{\sqrt{C}}{C}$

$x = k \pm \frac{2}{\sqrt{C}}$

The equations to be solved are presented herein:

$-3 = k -\frac{2}{\sqrt{C}}$

$5 = k + \frac{2}{\sqrt{C}}$

Now, the solution of the system is:

$-3 +\frac{2}{\sqrt{C}} = 5 -\frac{2}{\sqrt{C}}$

$\frac{4}{\sqrt{C}} = 8$

$\sqrt{C} = \frac{1}{2}$

$C = \frac{1}{4}$

$k = 5 - \frac{2}{\sqrt{\frac{1}{4} }}$

$k = 1$

The equation of the parabola is:

$y = \frac{1}{4}\cdot (x-1)^{2} -4$

Lastly, the graphic of the function is included as attachment.

3 0

3 years ago