Answer:
Option D
Step-by-step explanation:
Generally the equation for Margin of Error is mathematically given by
Condition for Largest M.E
n has to be smallest and Z value has to be largest.
Where
From options
Smallest 
Largest Z value respects to 
Therefore
n= 300, confidence level 95%
Option D
The modal and mean mark of the frequency distribution is 5 and 4.83 respectively.
<h3>Mean and mode</h3>
Mode refers to a mark which reoccurs most in a frequency distribution.
The total number of students who wrote the test = 2 + 3 + 4 + 6 + 10 + 4 + 3 + 2 + 1 + 1
= 36 students
Mean mark = Total mark / Total students
= (2×1) + (3×2) + (4×3) + (6×4) + (10×5) + (4×6) + (3×7) + (2×8) + (1×9) + (1×10) / 36
= (2+6+12+24+50+24+21+16+9+10 / 36
= 174/36
= 4.83333333333333
Approximately,
Mean mark = 4.83
If 25% of students failed,
Number of students who failed = 25% of 36
= 25/100 × 36
= 0.25 × 36
= 9 students.
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Answer: The change represents growth with 89% of growth rate.
Step-by-step explanation:
The exponential function is given by :-
... (i)
Where , A = initial value , b= multiplicative factor and x= time period
- We call 'b' growth factor when b>1, we can write b= 1+r , where r is the rate of growth.
- We call 'b' decay factor when b<1 , we can write b= 1-r , where r is the rate of decay.
The given function : 
.
By comparing this to (i) , we get
b= 1.89 > 1 , thus it represent the growth.
Also,
i.e. Percentage rate of growth = 0.89 x 100 = 89%.
Answer:
150
Step-by-step explanation:
Multiply 3 x 5 x 10
