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Fofino [41]
3 years ago
13

Point E is located at (2, −3), and point F is located at (−2, −1). Find the point that is 3 over 4 the distance from point E to

point F.
Mathematics
1 answer:
irakobra [83]3 years ago
3 0
It woud be very far.<span>Explain how you would graph the line containing a slope of –1/5 that goes through the point (1,–4).</span>
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A jar contains 45 red candies and 60 black candies. Suppose a candy is selected at random. What are the odds against selecting a
uysha [10]

Answer:

3:4.

Step-by-step explanation:

To work this out we need to find the highest multiple of 45 and 60.

15 is the largest number that goes into both of them so what we are going to do now is divide both number by 15.

45 divided by 15 = 3

60 divided by 15 = 4

Therefore the odds of selecting a red candy is 3:4.

Hope that helps. x

7 0
2 years ago
X - 2y + 2z = -22 <br> x + 3y - z = 03 <br> x + 2y + 3z = -15
scZoUnD [109]
What is your question?
7 0
3 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
3 years ago
I need to understand question 14 and 15 and the last one cut off for tens in one
sp2606 [1]

                                                 Question # 14

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am less than 20.

  • So the number 'x' must be less than 20 i.e. x < 20

I am more than 13.

  • So the number 'x' must be greater than 13 i.e. x > 13

I am less than 17.

  • So the number 'x' must be less than 17 i.e. x < 17

Finally:

I am 4 more than 12

i.e. 12+4 = 16

Thus, the number is x = 16

                                               Question # 15

Part a)

Given the numbers

10     11     12     13     14     15     16     17     18     19     20

Let 'x' be the number

The condition breakdown:

I am more than 10.

  • x > 10

I am less than 20.

  • x < 20

I am more than 12.

  • x > 12

I am less than 15.

  • x < 15

As the numbers left after all the conditions are fulfilled are 13 and 14.

  • But the last condition is, of the numbers that left, the number is greater than all the remaining numbers.

So, from the remaining number 13 and 14;

14 > 13

Thus, the number x = 14

Part b)

Drawing the number 14 in the place value:

          Chart

Tens                Ones

1                         4

6 0
3 years ago
If x-y=1 and xy= 56 then find the value of x+y​
tester [92]

Answer:

x + y = ±15

Step-by-step explanation:

Step 1: Write out systems of equations

x - y = 1

xy = 56

Step 2: Rearrange 1st equation

x = y + 1

Step 3: Substitution

(y + 1)y = 56

Step 4: Distribute

y² + y = 56

Step 5: Solve for <em>y</em>

y² + y - 56 = 0

(y - 7)(y + 8) = 0

y = -8, 7

Step 6: Plug in <em>y </em>to find <em>x</em>

x - 7 = 1

x = 8

x - (-8) = 1

x + 8 = 1

x = -7

Step 7: Find answer

x + y = ?

8 + 7 = 15

-7 + -8 = -15

So both 15 and -15 could be the answer.

3 0
3 years ago
Read 2 more answers
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