1. 55
2. N/A - Sorry. I can’t see the numbers properly.
3. 180
6/74 i think. So #banananutmuffin/#muffinsintotal
Answer:
a) see below
b) 40x20 meters
Step-by-step explanation:
Write down what you know:
- The area of the enclosure is length*width, so

- The length of the fencing is 80 meters, so

Now we have to combine these two equations above, and get rid of y in the process.
First rewrite the second as:

Then substitute for y in the first:

b) To maximize A, find the zero of the first derivative:

So y = (80-40)/2 = 20 meters.
(13-2x)(13-2x)
(13+-2x)(13+-2x)
(13)(13)+(13)(-2x)+(-2x)(13)+(-2x)(-2x)
169-26x-26x+4x^2
4x^2-52x+169
I hope that's help !
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