Answer:
Following are the responses to the given question:
Explanation:
Following are the difference in the speed and accuracy:
The biggest difference was its tone between both the cup method as well as the Morse code. One should talk using cup system and sequence system and let its covering be understood in Morse code, just a series of beeps weren’t tangible... Secondly, a method of cup involves a range string. Rukun Negara is often distributed by cable, but this is a greater range. It reaches concurrently in those other areas.
In the case of using the string method for the block, its distance and stiffness of the string are limited and the barriers are eliminated. It will certainly be convenient and clearer if one utilizes Sign language.
If two experts are acting like such a machine on both sides, their information between both the 2 persons is smoother and quicker as they will not have to wait for data from a third person which may create another pause at the time.
Morse code is faster, eventually. For some very small periods when sensitive information is not transmitted, strings or cup methods must be reserved.
Force required is 100 N
<u>Given that;</u>
Rate of acceleration = 5 m/s²
Mass of object = 20kg
<u>Find:</u>
Force required
<u>Computation:</u>
Force = Mass × Acceleration
Force required = Rate of acceleration × Mass of object
Force required = 20 × 5
Force required = 100 N
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Considering that the grasshopper starts on the ground and lands on the ground, there is no change in elevation. The range of the grasshopper is given by: <span>R=<span><span><span>v2</span>sin2θ</span>g</span></span>
If we now take the information that this is a maximal distance, the maximum range is given when the angle of launch is 45 degrees. This yields the equation: <span><span>R<span>max</span></span>=<span><span>v2</span>g</span></span>
We know R_max=0.4 m and g=9.8 m/s^2, so we can solve for v: <span>v=1.98m/s</span>
We are asked for the horizontal component, which by trigonometry is: <span><span>vx</span>=vcosθ</span>
We again take our angle of launch as 45 degrees and arrive at: <span><span><span>vx</span>=1.40m/s</span></span>
The trade winds are located about 30 degrees north and south of the equator.