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lesya [120]
2 years ago
11

what is the name of the tool that allows you to copy two or more shapes into a single part? when working with 3D

Physics
1 answer:
Anna [14]2 years ago
8 0

Answer:

Modeling tool or Align tool. it depends what type of sandbox platform you use

Explanation:

1

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The mass of an object with 500 J of kinetic energy moving with a velocity of 5 m/s is
Ann [662]

40kg

Explanation:

Given parameters:

Kinetic energy  = 500J

Velocity = 5m/s

Unknown:

Mass of the object = ?

Solution:

Kinetic energy is the energy due to motion of a body. It is expressed as:

          K.E = \frac{1}{2} mv²

  m is the mass of the body

  v is the velocity

 To find the mass, make it the subject of the expression:

         m = \frac{2 K.E}{v[tex]^{2}}[/tex]

          m =   \frac{2 x 500}{5[tex]^{2}}[/tex] = 40kg

Learn more:

Kinetic energy brainly.com/question/6536722

#learnwithBrainly

4 0
3 years ago
In order to prevent injury in a car crash, it is recommended that you _______. Increase the initial velocity of the collision.
Vlad1618 [11]
Increase the change in momentum of the collision
5 0
2 years ago
What type of relationship exists between acceleration and mass?
likoan [24]
Here, you can derive that by numerical method, as follows:
F = m.a
m = F/a

So, here we can see when we decrease one, other increase by same effect; we can say they are "Indirectly Proportional" to each other!

Hope this helps!
7 0
3 years ago
A 5.00-A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5 * 1028 free ele
evablogger [386]

Answer:

a)n= 3.125 x 10^{19 electrons.

b)J= 1.515 x 10^{6 A/m²

c)V_{d =1.114 x 10^{4m/s

d) see explanation

Explanation:

Current 'I' = 5A =>5C/s

diameter 'd'= 2.05 x 10^{-3 m

radius 'r' = d/2 => 1.025 x 10^{-3 m

no. of electrons 'n'= 8.5 x 10^{28}

a) the amount of electrons pass through the light bulb each second can be determined by:

I= Q/t

Q= I x t => 5 x 1

Q= 5C

As we know that: Q= ne

where e is the charge of electron i.e 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

n= 3.125 x 10^{19 electrons.

b)  the current density 'J' in the wire is given by

J= I/A => I/πr²

J= 5 / (3.14 x (1.025x 10^{-3)²)

J= 1.515 x 10^{6 A/m²

c) The typical speed'V_{d' of an electron is given by:

V_{d = \frac{J}{n|q|}

    =1.515 x 10^{6 / 8.5 x 10^{28} x |-1.6 x 10^{-19|

V_{d =1.114 x 10^{4m/s

d) According to these equations,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

If you were to use wire of twice the diameter, the current density and drift speed will change

Increase in the diameter increase the cross sectional area and decreases the current density as it has inverse relation.

Also drift velocity will decrease as it is inversely proportional to the area

 

5 0
2 years ago
Read 2 more answers
Both cars start from the same point. Which describes the motion shown?
evablogger [386]
Is there a graph we can look at?
4 0
3 years ago
Read 2 more answers
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